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Suppose I invest $1000 on 1 Jan each year, and it earns interest at 12% pa, compounded monthly. I start on 1 Jan 2022. How much will I have on 31 Dec 2030? Let $An be the amount the nth deposit grows to. So, $A1 is invested for all of 2022, 2023, 2024, ... and 2030, so for 9 years: A_1 =...

Commenting just from reading the paper, not checking answers / methods in detail: 2013 paper: I would not worry about Q8, plane geometry is now only considered as prior knowledge. Q11(e) and Q12(a) is no longer in the syllabus. Q13(b) part (i) is possible to ask, though unlikely, and part...

Recognising that you can't do something and seeking help is the opposite of dumb.

The important thing to recognise is: if interest is charged at 12% pa, and compounded yearly, then interest will be charged once at 12%, so if you owe $A at the start of the year, the amount owing at the end of the year (before any payment is made) is A \times \left(1 +...

No answers provided as all parts are "Show"

Ok, here are some questions to try, taken from a variety of topics: There is a typo in the question... it should say that F(x) = \int \cfrac{x + 1.5}{x^2 + 3x}\ dx for the rest of the question to work.

Those are just advanced questions, the BoS trials included an advanced / 2u level paper in 2013, 2014, and 2015.

For anyone who hasn't noticed, comments on the 2021 BoS MX2 exam have been posted. The distributions of answers for the MCQ have been posted here.

Firstly, be careful not to mix up the terms here. Calorimetry is a technique for determining enthalpy changes by measuring temperature changes. Colourimetry is for determining concentrations by measuring the absorbance of light in the visible range of the electromagnetic spectrum. And the...

MX2 Multi-choice. Percentages are the proportion of respondents selecting each option. Correct answer bolded and in green. Options Q1 Q2 Q3 Q4 Q5 Q6 Q7 Q8 Q9 Q10 A 27% 23% 5% 59% 14% 45% 0% 23% 9% 9% B 59% 9% 0% 5% 55% 9% 95% 14% 5% 68% C 5% 68% 5%...

Also, some general thoughts / comments based on my observations in marking: On q11(c)(ii), the working can be simplified as follows: \begin{align*} t &= \int \cfrac{dv}{g - kv^2} \\ &= \int \cfrac{dv}{g - \frac{g}{{V_T}^2}v^2} \qquad \text{using the fact that $\ddot{x} = 0\ \implies\ {V_T}^2 =...

The paper was challenging... and then some. :)