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Got 29m. I just did table of values for 0 to 7, and showed the distance travelled. Reckon I'll get marks? :p

Yeah it is sqrt(450), I read on another thread. How did you get that though?

http://www.wolframalpha.com/input/?i=375-e%5E%280.04t%29+from+0+to+150 Like this

I reckon I'm looking at 60 worst case, 66 best case. So probably somewhere in between :)

Yes. Your raw mark will be aligned (in this case, to probably a B6) and that mark is used to determine your ATAR. :)

Based on my earlier thread, that'll go to about mid band 5.

$Isn't it $ x^{2} = y + 4\sqrt {y} + 4$?$

Apparently about very high band 4, low band 5.

Can't remember my exact answer, think it was 193 months.

x = \frac {1}{2} $ and $ A = \frac {1}{48}

I got all same answers for i, ii, and iii. Hopefully I scrape 6 marks from Q16 :P

Damnit. Instead of of doing (\sqrt {y} + 2)^{2} I just squared both terms, forgetting the middle term so I got y + 4. FML

Woah, given that, I may actually just sneak in a B5! That'd be great!

How did you show similarity?

Damn. I'll probably just miss out. :(

\lim _{ x\rightarrow 2 }{ \frac { { x }^{ 3 }-8 }{ { x }^{ 2 }-4 } } \\ \\ \indent = \lim_{x\rightarrow 2}{\frac {(x-2)(x^{2}+2x+4)}{(x+2)(x-2)}} \\ \\ \indent = \lim_{x\rightarrow 2}{\frac {x^{2}+2x+4}{x+2}} \\ \\ \indent = \frac {2^{2}+2(2)+4}{2+2} \\ \\ \indent = \frac {12}{4} \\ \\ \indent = 3

Got confused with question 6. 10 is B.

What do you guys think will be the raw cut-off for a B5? :)

I didn't solve it. I just derived N, and set it to dP/dt.

Yep I did that too!