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I haven't done as well for past 2 subjects, let's hope this goes well :) gl all.

Expand 2a(x+1)^2 +b(x+1) + c Rearrange. \\2x^2-5x+7 \\2a(x+1)^2+b(x+1)+c\\2ax^2+4ax+2a+bx+b+c\\(2a)x^2+(4a+b)x+(2a+b+c)\\\\2x^2-5x+7 \\\\ $You know that $ 2a = 2 \\ \therefore a = 1\\$You know that $ -5 = 4a + b $ \\ -5 = 4 + b \\ \therefore b = -9 \\ 7 = 2a + b + c \\ 7 = 2 - 9 + c \\ c = 14

I'll keep that in mind for this afternoon. Hopefully there isn't anything too difficult.

So I am guessing, generally there are no special 'shortcuts' to the Q16's with "complicated" RTPs?

Third line, he expanded the 463900(1.005^n - 1 ) \\360000(1.005)^n - 463900(1.005)^n + 463900 = 180000\\283900=103900(1.005)^n

Try closing Steam, might make you work more productively. :oink:

Anyone have a feeling Q16 will be a killer?

Do update us on what you did on the day ;)

re: HSC Physics Marathon Archive Couldn't they ask you any one of them?

I don't think it matters. If you label it.

You know the area of the the derivative graph is the total distance traveled. It is 4 because that is the largest (positive) area ?

Re: HSC 2015 2U Marathon Use LaTeX and enclose LaTeX with tex tags : "[ tex ] ... [ /tex ]"

I thought a,b,c could all be correct be D was the most correct. Now that you actually asked, my logic is ..

Did you do part (ii), I am struggling to do it . _ .

OP is just Pythagoras OP = sqrt ( (3R)^2 - r^2 ) OP = sqrt ( 9R^2 - r^2 ) EDIT: fixed my error ~

Nothing compared to you, 393. :shoot:

No solutions exist for x^2-2x+9=0 so I am guessing it is all real x?

Are you 393? :D

LOL. okay.