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Pretty sure the answer is wrong. If you want to go about the long way using distance formula, you can still work out the radius straight away r^2 = (6-3)^2 + (7-4)^2 r^2 = 9 + 9 r^2 = 18 Therefore equation of the circle is (x-3)^2 + (y-4)^2 = 18 And the radius of the circle is simply...

7. Pretty sure this is beyond the scope of the course (like some of your other questions), but I happened to research this during my HSC too, I don't know the specifics but iirc the 4 hydrogen atoms do not fuse immediately, there is more than just one single reaction and between the reactions...

Not sure if I understand what you're trying to say or maybe you're overthinking it. Might have to let someone else clear this question up since physics isn't my strongest subject anyway

If you're talking about something like CH4 in terms of being the molecular formula of the compound, then no. CH4, C2H8, C3H12 are all different (C2H8 and C3H12 don't exist though as a side-note), but if CH4 is treated as an empirical formula then yes it's the same as C2H8 and C3H12.

Use W=Fs To find F, use F = ma F = 10000*9.8 = 98000 N s = W/F = 5.73*10^11/98000 = 5846938 m = 5847 km

I find that sort of notation confusing myself, but basically you should recognise platinum as an inert electrode that doesn't actually take part in the reaction, so the reactions that are taking place is the oxidation of magnesium and reduction of mercury. You are given the reduction...

4. As long as the ball is moving, there will be friction between the ball and the air molecules which will decrease the velocity of the ball. The velocity of the wind does not have to be greater than the ball for it to decelerate. Even in a case where there is no wind at all, there are still air...

3. CH2 (methene) doesn't exist, if its treated as an empirical formula then it's the same as C6H12 since it's just simplified as a ratio of atoms, but alkenes require a double bond between two carbon atoms, but there is only one carbon atom in this case

1. The aluminium oxide (Al2O3) is inert and therefore prevents the aluminium from undergoing a redox reaction with another substance as the Al2O3 is there to provide a barrier for the aluminium. Aluminium oxide is also impervious to oxygen and water and therefore aluminium foil is good for...

Oh of course, I'm stupid D: The working you provided seems correct, perhaps OP may have made a typo

I'm on holidays atm so I don't have any writing equipment to work out this question, but try splitting the trapezium into a right angle triangle and a square and equate the areas. i.e. Area of trapezium = Area of square + Area of rectangle Then rearrange so that y is the subject

Classical music helped me concentrate much more than usual, I find other genres distracting though

Guitar 4 lyfe

Here are some free ones from the BOS resources, can't guarantee that they'll necessarily be helpful for you though. http://www.boredofstudies.org/courses/science/chemistry/1484085303_2016_Chemistry_Notes.pdf http://www.boredofstudies.org/download.php?id=15759

Although it's unlikely to be asked to distinguish between them you should still know it, just in case if there's like a 1 or 2 marker on it. And the LDPE and HDPE production processes are quite different so if it's a question asking you specifically on how LDPE or HDPE is produced, then you will...

I felt it was much easier compared to previous years, except I made so many silly mistakes I couldn't even end up proving some q12 and q13s -_- Time was a bit of an issue for me since I didn't end up checking over my paper thoroughly and seeing where the mistakes I made where, but the questions...

I meant the ratio of reactants is 3:1

Yeah I wrote out the equation, but wrote some bs working after that because I hadn't really come across any similar question to that, probably should've spent some more time on chemistry instead of the whole week before on physics lol

For that question I could only think of mentioning temperature, pressure and catalyst. I had a huge mind blank and couldn't think of anything else to talk about (like the 3:1 ratio, monitoring impurities etc) hopefully I don't lose too many marks for that since it was out of 7 :/

I didn’t find it very difficult apart from a few multiple choice questions which were harder. I only had trouble on that heat of combustion question, other questions were all quite straightforward. Hoping for 90+ raw