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This guide is fab, thank you! Just a question: I see that you've colour coded your highlighting. What did you use each colour for?

Hi, could you please PM me samples for Dobson poetry, 1984/Metropolis, Speeches and King Henry IV?

http://puu.sh/h5tGY/a4d5eeeb27.png My solution but not sure if it is the fastest. Your problem may have been that you assumed the hypotenuse in the cylinder was horizontal, which it is not.

Hi, for some exam questions I have seen they might give an equation (say f(x)=e^x - 4) and ask why the x coordinate of any intersection points of f(x) and its inverse satisfy an equation (e^x - x - 4 = 0) which obviously requires you to equate f(x)=x. But in the textbook I have seen a...

24(a) Number of ways for us to decide which meal is NOT chosen = 5 This leaves us with 4 meals for the diners to choose from. All the meals have to be chosen. But ONE meal has to be chosen exactly twice. Out of the 4 remaining meals, this can be chosen in 4 ways. Let’s arrange the meals in order...

idk if the link works but https://9eeba4054ee764a743f35bb25b5f907e66151207.googledrive.com/host/0ByEFYhkkDQBKUmxzb0Q4MEswQ3c/Year%2012%20-%20HSC/Maths/Past%20Trials/James%20Ruse/3U/James%20Ruse%202009%203U%20Trials%20&%20Solutions.pdf It's the 2009 3U Ruse paper, q5

Hi, so I'm stuck on this question... There are 8 red, 9 green and 6 yellow cards in a pack of cards. Five cards are drawn. Find the probability of obtaining 2R, 3G if it is known that at least 1 card is green. My answer was (8C2 x 8C2)/(22C4) (I assumed one was already green) The solution...

Re: HSC 2015 3U Marathon I got 4! x 3! x 2 = 288 arrangements?

very simple... your area is bounded by the y axis so you should consider integrating the curve with respect to y... i.e. since y=ln x, x=e^y So just find \int^{4}_{2} e^y dy

Hi, Basically the question is asking you to solve z^4=\sqrt{2}+\sqrt{2}i Try letting z=rcis\theta The process is exactly the same as solving a standard root of unity question... r^4 cis4\theta = 2cis\frac{\pi}{4} \Rightarrow r^4=2,4\theta=\frac{pi}{4} +k2\pi and so on.

Thanks for the clarification :)

Yes I know the solution should go like |-tan^2 x|<1 \Rightarrow tan^2 x<1 \Rightarrow -1< tan x < 1 etc. I just wanted to know whether tanx=0 should be included... i.e. using my thoughts above I might get -1<tanx<0, 0<tanx<1

Hi, I have a question about conditions of the limiting sum formula S=\frac{a}{1-r} ... The condition is that |r|<1 but I'd just like to clarify whether r=0 should be included in this, because my teacher explained it as a literal limit i.e. your series will approach S but never actually...