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I have friends in high places... lol

Omg help meee pleeeasse~!!!!!

Question 22 (7 marks) Marks A chemistry student is required to produce 25.0 mL of 0.01M sodium carbonate solution. She was provided with the following forms of sodium carbonate: • A bottle containing 200.0 mL of 0.05M sodium carbonate solution. • A container of solid sodium carbonate...

Question 25 (2 marks) Marks Equal volumes of lead nitrate solution and sodium iodide solution, each with a concentration of 0.10mol L-1, are mixed. A yellow precipitate of lead...

lol thanks realise haha. MORE: My heart aches every time I think of you, I long to see you and your perfect figure, just to talk to you, and be in your presence. I want to be with you more than anything. You are older than me but not by much at all, I think I would be a perfect guy for you...

My crush, you have had the most incredible impact on my life, beauty and intellect and sophistication and elegance and sexiness where absolutely redefined when I met you. You just have it all, and are just amazing. I love you so much, please, will you love me back?

WHAAT i did exactly that, and my calculator said a different number... LOL gotta fix calculator it seems.

A beaker contains 100mL of silver sulfate (Ag2SO4) solution at a concentration of 1.0 x 10-5 mol L-1 . What is the mass of silver ions in the beaker? (A) 1.0 x 10-5g (B) 2.16 x 10-4g (C) 1.08 x 10-3g (D) 1.5 x 10-2g

what a stupid thread lolz

Ah thanks, I see what I did wrong now, I did sqrt before adding 4a^2p^2 to -2a^2p^2

Ive done this ten times, yet I get the wrong answer apparently. I can SWEAR im right here. The answer says its a(p^2+1) i) Find an expression using the distance formula for PS on the parabola x=2at, y=at^2, and at P its with parameter p. S is the focus, (0,a) So basically its sqrt...

NOONE HAS ANSWERED THE FIRST QUESTION ON THE FIRST POST! plz help guys! How to do the question on my first post here??

I figured out its all good.

K now a new one.... Find the equation of the chord of the parabola joining the points with parameters: a) 1 and -3 on x=2t, y=t^2

No its perfectly easy to understand dw, thanks man! I see where I went wrong now.

Yea I tried and ended up with 9x*2+27=4y^2+16. Idk how to get into the answers form.

yea first one is (x-3)^2=y+1, second one is 4(y+4)^2-9(x-1)^2=36

Pleaase help meee omfgg!!!!!!!

OH AND HELP ME WITH THIS ALSO plz, eliminate the parameter and hence find the cartesian equation of the curve x=1+2tantheta, y=3sectheta-4

Find equation of parabola with vertex (3,-1) and 4x+y-7=0 is a tangent. Fuck this is annoying me.