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Re: HSC 2013 2U Marathon 4sin^3 x cosx + 8x^2 sinx cosx + 36x^8 sin^2 ?

Re: HSC 2013 2U Marathon lmfaoooooooooooo

100% pure beta not even a scent of alpha in you m8

Re: HSC 2013 2U Marathon post a question sy ;)

Re: HSC 2013 2U Marathon he's a true moeeeeeyyyyyy :D

Re: HSC 2013 2U Marathon $i) Consider$ \ \ f(x) = \ln x + \ln \sqrt{x} $ii) Write f(x) in the form of$ \ \ \ln (g(x)) $iii) Find the area bounded by g(x) the y axis, y=0 and y=5 in exact form$

have 2 calculators one in radians and one in degrees label each one with R and D, whenever you see a trig question with any trig ratios... or the value pi radians should jump to your head. read the question carefully before thinking its radians ie tan(pi^degrees)

watch out motherfuckers not always n>= 0 : D

Re: HSC 2013 2U Marathon no wonder you're in general maths

Re: HSC 2013 2U Marathon y=ln(x) mad bro?

Re: HSC 2013 2U Marathon for integrals leave in exact form (easier for marker to mark it) probability it doesnt even mattere i'd say leave any approximation methods (Simpsons rule or trapeziodal rule) in decimals. exact values for trig, integrals, annuities ect are better so you can use in...

Re: HSC 2013 2U Marathon :) edit great why cant i write in his quote

Re: HSC 2013 2U Marathon :) $was first principal $\frac{ f(h+m) - f(x) }{m} ? \frac{\frac{sin(h+m)}{h+m} -\frac{sin h}{h}}{m} is this rights so far? 1

Re: HSC 2013 2U Marathon xD MEMORIES GREATER THAN LOGIC ANY DAY OF THE MONTH BUDDY

Re: HSC 2013 2U Marathon can you calm down i thought the whole state knew that step its not my fault i dont like showing every step Mr sy :D

Re: HSC 2013 2U Marathon I) u=x\ \ \ \ v=lnx u'=1 \ \ \ \ v'= 1/x \frac{d}{dx}(xlnx)\ \ = u'v+v'u\ \ (1)(lnx)+1 \ \ = lnx +1 ii) \int_{1}^{3} lnx dx [{xln(x)-x}]_{1}^{3} =(3ln3 -3)-(ln1 -1) \ \ =3ln3 - 2 ---------------------------------------------------------------- $Find...

Re: HSC 2013 2U Marathon i) y=\sqrt{1-x^2} \frac{dy}{dx} = \frac{-x}{\sqrt{1-x^2}} M=\frac{-a}{\sqrt{1-a^2}}\ \ = \therefore \frac{-a}{b} \ \ since \ \ b=\sqrt{1-a^2} ii) $tangents gradient$ = \frac{-a}{b} \ \ $and OP is$\ \ = radius= \ \ \frac{rise}{run} = \frac{b}{a} \frac{-a}{b}...

Re: HSC 2013 2U Marathon as a matter of fact i'd really like that -_-

Re: HSC 2013 2U Marathon half the questions on here are Q12-14 hardness :)

Re: HSC 2013 2U Marathon but i cant because sy's questions are hard