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Re: HSC 2013 3U Marathon Thread $i) Find the probability that in$ \ \ (n+k) \ \ $tosses of a fair coin, there will be$ \ \ n \ \ $heads$ $ii) Hence explain why$ \sum_{k=0}^n \frac{\binom{n+k}{n}}{2^{n+k}} = 1

lmfaooo nakruf strong representation of the DIAMONDA

sy the <diamond> where is the diamond trollface.jpg

sy123 ibn sina :D

Re: HSC 2013 3U Marathon Thread my first method was totally wrong i realised after 2 hours :D total number of ways they can be arranged is 7! =5040 number of ways all couples sit together = 3!2!2!2!2! =96 number of ways 2 couples sit together but other 2 random = 5!2!2! =480 number of ways...

Re: HSC 2013 3U Marathon Thread $$$$$$$ Hurry the hell up sy make another question that we can all benefit from not only the 4Uers $$$$$$$ :D

Re: HSC 2013 2U Marathon i skipped so many steps because i cbfed showing it using this latex bs wastes to much time and mathewYan can you please tell me where i made mistakes?

Re: HSC 2013 2U Marathon too easy sy :D

Re: HSC 2013 2U Marathon cosec^2 x -1 = cot^2 x \ \ \ $simple substitution into f(x) $ \ \ \int_{\frac{-\pi}{4}}^0 \ \ \frac{1}{\sqrt{cot^2x}} dx \ \ \ \ \int_{\frac{-\pi}{4}}^0 \frac{1}{|cotx|} dx \ \ = \ \ \ int_{\frac{-\pi}{4}}^0 |tanx|\ \ = \ \ $(-ln(cosx)) _\frac{-\pi}{4}^0$...

Re: HSC 2013 3U Marathon Thread i) \int_0^{\pi /2} \sin^{2k} x \cos x \ dx = \frac{1}{2k+1} \int_0^{1} \ u^{2k} \ \ du = \left(\frac{x^{2k+1}}{2k+1}\right)_0^1 = \frac{1}{2k+1} ii) \int_0^{\pi /2} \cos^{2N+1} x\ dx $ can go fuck itself with its binomial 7 marker bullshit $

Re: HSC 2013 2U Marathon i) $ point R(p,q) sub into$ \ \ y= \frac{1}{x} \ \ = q= \frac{1}{p} ii) \frac {dy}{dx} = \frac{-1}{x^2} \ \ $sub x= p to get gradient$ \ \ M=\frac{-1}{p^2} $y-y_1= m (x-x_1)$ \ \ y-q= \frac{-1}{p^2}(x-p) \ \ y- \frac {1}{p} = \frac{-x}{p^2} +\frac{1}{p}...

hey fag SY123 BRAH

dont you just: [ln(x-x^3)] from -2 to -e and you get ln(6) -ln(-e+e^3)= ln(6/(e(-1+e^2))) = ln(6/-1+e^2) - ln(e) hence that girls solution ln(6/e^2 -1) -1 im pretty sure she didnt want the u substitution method but its better that you show your supreme ways sy ;)

flop lol how gay

Wooooww when did this wikipedia thing come out is it another technological advancement?

Fuck didnt work

Yes yes no yes yes

go spam frost again

:spin:you w0t m8

you better accept it