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dont you sum it using gp and do shit to it i thought you would be used to those kind of questions with all the notation and theory stuff

i bet u bossed the last part

i got to part iii wrote half a page of working and just sacked the rest might get 1 or 2 lol

equiangular =/= congruent

wrong

f=ma that is all you need to know

when you do f(a-x) can you do it as f(-x+a) so sketch f(-x) first then shift it a units to the left?

expand (2+i)(3+i) and deduce that \tan^{-1}\frac{1}{2}+\tan^{-1}\frac{1}{3}=\frac{\pi}{4}

defqon1

this is good if you have a surd on bottom letting u = surd makes it so that when you differentiate it it easily goes away

thats painful look for an easier substitution

+1 you cant stress during the exam

lol mate you and zyzz

are you retarded this question is repeatedly asked and there is a raw mark thread on the first extension 2 forum page

\int_{1}^{2}\frac{1}{x\ \sqrt[]{2x-1}}\ dx

lol my class went complex > polynomials > conics > integration > volumes > mechanics > harder 3u > graphs

i am yr 12 and wat is dis

http://community.boredofstudies.org/showthread.php?t=266583 deja vu

a bit different

\\it\ is\ given\ that\\\\ cos\ k\theta =2\cos\theta \cos(k-1)\theta-\cos(k-2)\theta\\\\ show\ that\\ \\ \cos2\theta=2\cos^2\ \theta-1\\ \cos3\theta=4\cos^3\ \theta-3\ \cos\theta\\ \cos4\theta=8\cos^4\theta -8\cos^2\theta+1\\\\ The\ T\ polynomials\ are\ defined\ by\ the\ recurrence\ formula \\\\...