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projectile motion uses horizontal and vertical components anyway so its the same thing

use the force from part a to find the acceleration, then plug acceleration into v^2=u^2+2as

idk maybe i mixed up the vertical and horizontal components

it was like a table and it said choose the correct contribution of einsten and planck to quantum theory or something

what did you lads get for that einsten/planck mc? wording was absolute shit

nah i got 60 too fam

yeah should be parabolic i mean, i just said curved in the exam anyway so that would probably suffice

Should have had a circular path too, not a sharp bend

re: HSC Physics Marathon Archive probably 12 or something, getting up at like 6 tho to go over stuff, will probably stay in my head better then

You would have to write the specific applications of it, and why it is useful for those applications based on its properties

The observers on earth will perceive events inside the ship to take longer than they actually do for the astronaut, so say an event actually took 1 second on the spaceship, the people on earth will perceive this as taking longer, therefore the astronaut is actually experiencing time quicker than...

Meth tbh

lmao didnt end up finishing my D&T major work because I left it to the last minute, although it was quite complex so they'd probably account for that when marking

Q32 of the harder MC for ideas to implementation should be in eV not V, everything else is good tho, cheers

It will usually form smaller eddy currents in each metal slit, there will still be braking but it will be much smaller

top 3 Med Chem - UNSW Advanced Science - USYD Advanced Science - UNSw

Nah fam, in past marking guidelines for discuss questions they always specify it as for and/or against, just whether you had enough information etc.

Planck & Einstein's differing views on whether science is removed from political and social factors

Discuss is provide point for and/or against, if he provided enough information for it and related its properties to its use well, then he shouldnt lose marks

Its where it meets the y-axis, so if you have the equation hf=hf0+KE and you re arrange it to give your variables as KE and f, then you get KE=hf-hf0 then in the form y=mx+b, you get the y intercept to equal -hf0, which is also equal to the work function, and the gradient is equal to h from mx=hf