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Re: HSC 2014 4U Marathon - Advanced Level seriously if it was that easy i wouldn't have posted it here

Re: HSC 2014 4U Marathon - Advanced Level how do you know that plugging those values into the LHS gives you 8 without using a calculator? You cannot use a calculator for this question

Re: HSC 2014 4U Marathon - Advanced Level In trapezium (quadrilateral with one side parallel) with sides XY and ZU parallel, Angle UXY=6 degrees, Angle XYZ= 42 degrees. Point B is one side XY such that angle XBU = 78 degrees and angle ZBY = 66 degrees. If XY and Zu are 1 cm apart (vertically)...

Re: HSC 2014 4U Marathon - Advanced Level actually u can't find the exact value it converges to.. Change the question to 'explain why the series converges and roughly where it converges'

Lol why didn't u join some maths olympiad or something

Re: HSC 2014 4U Marathon - Advanced Level just to clarify, if the term has at least 1 digit which is 9, it is excluded from the series. So 1/998, 1/89 etc are all excluded

Re: HSC 2014 4U Marathon - Advanced Level It converges.

Re: HSC 2014 4U Marathon - Advanced Level what is the value of the infinite series, 1/1+ 1/2 +....+1/8+ 1/10 +...+1/18+ 1/20+....... Btw this is the 1/1+1/2+1/3+....+1/n except without any terms with a 9 in the denominator

Are u guys like part of the physics olympiad or something? ?

Re: HSC 2014 4U Marathon let O be the center of a circle with diameter AB. C is another distinct point on the circle and D is the point on AB such that CBD is 90degrees. M is the point such that BMO is 90 degrees and lies on BC. BD is three times OM. find angle ABC

Re: HSC 2014 4U Marathon yep good job this was what I did lol. Hence why I told u to find an alternatuve solution which hinted that a very simple did exist

Re: HSC 2014 4U Marathon can u find another way without using so much trig

Re: HSC 2014 4U Marathon sort of difficult

Re: HSC 2014 4U Marathon please ignore my previous post.

Re: HSC 2014 4U Marathon integral from (6^(1/2) + 2^(1/2))/2 to 1: (1+x^2)/(1+x^4) using the substitution u= x-(1/x) you cannot use any 4u specific integration formulas such as IBP, partial fractions, inverse tan integral, etc. Only 3u concepts such as u substitution.

Re: HSC 2014 4U Marathon using the converse of pythagoras' theorem was one way i did it

Re: HSC 2014 4U Marathon - Advanced Level Noope

Re: HSC 2014 4U Marathon - Advanced Level I thought this one was a good one. A function f(x) is continuous for x>0, and (x-1)f(x) is differentiable for x>0 and its derivative is 1/x. Find f(x) for x>0

quite true, where are the solutions???

Re: HSC 2014 4U Marathon - Advanced Level yeah good I showed that GHC is equal to BGH using basic angle chase to prove that CH is parallel to BG though. Other than that, we pretty much did the same thing. Oh and yeah I don't think this is HSC