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just sub it in lol z^13 = w w^11 = z z = w^11 = z^(13*11) = z^143 hence z^142 = 1 z is some 142nd root of unity hence z = cos(2πm/142) + isin(2πm/142) for integer m Im(z) = sin(2πm/142) = sin(πm/71) = sin(πm/n) where n = 71

as long as there's no conics or crazy circle geometry it's prob fine for current syllabus

why would you do that bruv 1. ∫ 1/sqrt(x^2+1) dx probably isn't showing up in the HSC (maybe in trials) 2. you can just multiply by some asspull on the top or do an asspull trig sub x=tan(theta) dx = sec^2(theta) dtheta I = ∫ 1/sqrt(x^2+1) = ∫sec^2(theta)/sec(theta) dtheta = ∫ sec(theta)dtheta...

pure unadulterated copium

write it out and group it a bit LHS = (s0+s1+s2+...+sm)(t0+t1+t2+...+tn) = s0(t0+t1+t2+...+tn)+s1(t0+t1+t2+...+tn)+s2(t0+t1+t2+...+tn)+...+sm(t0+t1+t2+...+tn) = s0 sigma + s1 sigma + ...+ sm sigma = other sigma (sigma) =RHS qed same thought process for other case

if you wanna get a single term like x^4 it seems way faster to just find certain coefficients from (1+x)^3 and multiply by the other coefficients from (1+3x)^8 or smth

what the fuck is double sigma notation

why would I do it if my school already offers physics 💀 TAFE or SDEHS are just alternatives if you rly wanna do physics (or some other subject) and are unable to cuz of ur school

💀 you could still do it via SDEHS or smth if it hurts your ego that much

blud it'd be doing HSC Physics via TAFE WHILE IN HIGHSCHOOL STILL bruh

guilttrip the school?

twas a joke do you think an asian parent would rather their kid take physics at TAFE and still get a HSC mark or drop physics bro

… You prob shouldn’t be picking your subjects from just scaling but ok. You take the HSC course via TAFE, however, you still sit the HSC and hence, still get a HSC mark.

… Schools can actually have a shortage of teachers for certain subjects At selective schools, they don’t want everyone picking only STEM (heard this somewhere) so they can’t have stem for everyone. If his school has a teacher shortage for those subjects specifically, I highly doubt it’s ranked...

If you rly wanna do it you can do it via TAFE or SDEHS or smth (basically taking it online instead of at school I think)

what ru picking

bro misandry isn't even a real thing

I hate to break it to you. If you can't solve that trivial question, you're bound to get a Band 4 in Mathematics Advanced.

Prove that all the zeroes of \zeta(s), where \zeta(s) = \sum_{n=1}^\infty \frac{1}{n^s}, are either negative even integers or complex numbers with \Re(s) = \frac{1}{2}.

since when was psych a subject wtf