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volunteers aren't paid

tan^-1(√2-1)+tan^-1[(1-(√2-1))/(1+√2-1)] =π/4 tan^-1(√2-1)+tan^-1[(2-√2)/√2]=π/4 tan^-1(√2-1)+tan^-1(√2-1)=π/4 2tan^-1(√2-1)=π/4 tan^-1(√2-1)=π/8

nah it's like top 99% of the population

im going uts med

med is med

w is a solution to z^3=-1 z^3+1=0 sum of roots =-b/a=0 -1+w-w^2=0 (6w+1)(6w^2-1) =36w^3+6w^2-6w-1 =-36 - 6(-1+w-w^2)-6-1 = -43-0 = -43

les go

probably a,b,c > 0 and a≠b≠c since this looks like an application of AM/HM rearranged a bit consider (a+b+c)(1/a+1/b+1/c) > 9 (a+b)(1/a + 1/b) > 4

You can't add days to your life, but you can add life to your days.

do you happen to also be 6'6

school tryna sabotage you fr

roughly 35-40

if you've covered everything, you probably don't learn any content after trials you may learn some heuristics/exam technique tho

a. 9 choices for first digit (can't be 0), 9,8,7 etc for next digits total = 9*9*8*7*6*5*4*3*2*1=9*9! = 3265920 b. 9 choices for first digit (can't be 0), 10 for each subsequent digit total = 9 * 10^9 [9 other digits]

perms and combs is very difficult

:awesome:

how much you good with $300 per exam?

.95 inc

still are