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I think you'd be right if water were in gaseous form.

Yeah true. The Cartoonist needs to get a life and stop pissing others off. The Prophet Muhammad is the most influential figure in Islam exc. Allah and misrepresenting him in that particular way is not good.

Yeah, just sub in what i got for my first post and u should get it. ie sub in a+b=-m and ab=n into x=[m^2-2n+-msqrt(m^2-4n)]/2n, it ends up working out :)

Yeah but says liquid state in equ.

for x^2+mx+n=0: a+b=-m ab=n Also, x=[-m+-sqrt(m^2-4n)]/2 ....1 for nx^2+(2n-m^2)x+n=0: zy=1 z+y=(m^2-2n)/n =[(a+b)^2-2ab]/ab =[a^2+b^2]/ab roots for last equ are: x=[m^2-2n+-msqrt(m^2-4n)]/2n But it's easy to solve the last equ using quadratic formula instead of all the...

My friend got a low band 4 in adv english and his ATAR was really good (95+) because of his science and maths results :)

Maths, probably.

I for one, am not interested in reading your random stories about your family and their employes or relatives. You should just get off BoS before you piss everyone off.

Yeah. I got the same thing :)

So I am guessing that you'd go to TAFE. That's good for most ppl on BoS as they don't have to see you at uni.

Hey, I should be thanking you. You summarised everyone's thoughts in a concise post.

Thanks for the rep Kazi. I keep trying to rep you but a message pops-up saying that I need to spread rep around before giving it back to u :(

Oh ok, thanks for the correction.

arg(z-2)=k.arg(z^2-2z) If mod(z-2)=2, then; arg(2)=k.arg(2z) [idk if this is correct] But, mod(z-2)=2 ie. z-2=2 or z-2=-2 Thus, z=4 or 0 but arg(0) is undefined ie. z=4 arg(2)=k.arg(8) arg(2)=3k.arg(2) k=1/3 This solution is probably incorrect as I'm rusty with 4u Gurmies, how did...

Re: 2009 HSC results by school lol haha.

Damn, i got k=1/3.

Yeah, going to UNSW and probably doing BCom/Bsci

Re: What is your confirmed ATAR? 96.3

Re: Math Ex2 scaling? Same, i thought i'd get 100+/120.

Chem-87 Phys-86 Eng-80 MX1-94 MX2-92