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On the other hand, I have to practise my writing in general. It's pretty much scribbled writing and many compliaints were made in regards to my writing in my maths trial exam.

Re: What UAI/course are you aiming for? Well, the core message I was trying to send is that having natural intelligence < trying your best effort to get all the required works done.

True. Many of my Korean friends in Korea went to America, England and came to Australia when they started their high school.

Re: What UAI/course are you aiming for? Your definition of "not much" is quite disputable and not clear in the sense that every individual is different. I will follow on from what you just said. You mentioned that it depends on the individuals. But don't you think different amount of...

If that's the view you hold, everything related to the academic system would be unfair wouldn't it be?

English predominantly deals with the aesthetics involved in the language and the silky road awaits for those who take in the language slowly and enjoy it. Good luck.

Re: What UAI/course are you aiming for? People who don't believe in themselves already have no grounds for 90+ UAI. To ShaonO: From reading several posts of yours, you seem to underestimate the amount of works involved to achieve 99+ UAI. Not all top 5 students from each school will get 99+...

I think your English has been quite above the bar from what I observe.

Well, there are two sets of same words, namely C & C and R & R.

Re: Preliminary HSC Yearly Exams I have mine from week 9 to 10.

I didn't initially do that. It was you who provided the working out.

P(2C'S together) = (7!)/(2! x 2!) P(2C'S NOT Together) = 1 - P(2C'S together) = 8!/(2! x 2!) - 7!/(2! x 2!) = 10080 - 1260 = 8820

I added 1 to both sides.

y+1= 2x^2 + 4x 1/2(y+1)=x^2+2x 1/2y+1/2+1=x^2+2x+1 (x+1)^2= 1/2(y+3)

Ok, first, you didn't give me the y +1 in the equation. I will re-do it for you, wait a minute.

Whatever method you use, if it works, use it. I used that method because that was easy for me.

Factorised form? I would personally use Quadratic formula to find the roots. If you didn't mean factorised form but complete equation, I would first go: 2x^2 + 4x - 5 = 2(x^2 + 2x -5/2) = 2(x^2 + 2x + 1 -7/2)...

So there's no problem getting your hole penetrated 100+ times during your school year?

Well, yeah. The idea is to get all desired value to make the "complete equation". I hope that cleared some up.

That's good. My ranks won't change... I really wanted to move up in ranks...I don't think it will happen. :mad: EDIT: I thought you said, you moved up in ranks, sorry!