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Bahaha, yeah I figured it out finally. Thanks jackson!

No, the angle isn't 90 it is 0. sin0 = 0. Even with your reasoning you're wrong, because torque would have to be a cos curve with your reasoning. torque is not current. With your reasoning, the answer would be A, because B, I and l remain constant. EDIT: OK I got it, the angle is 90, making the...

I don't get it? Isn't the force on a current carrying conductor F=BIlsin(theta)? That would mean force is proportional to the sine curve and thus be one.

I mean was the acceleration in the projectile question 9.8?

The lattice still has small vibrations at low temperatures. According to BCS theory, an electron will attract protons behind it, causing a small lattice distortion that creates a small positive field, attracting another electron. The electrons then exchange phonons and move as one particle...

The wire is perpendicular to the magnetic field, at that moment in time the motor would rely on momentum to push it to get it started, where torque is also at a maximum. Plus, the force on AB is actually down, I'm pretty sure of it. EDIT: Just noticed the arrow indicating it's up, but the...

Same here for 11 D, I really think F of AB should be a sine curve.

Yeah that was good, but was a 9.8 or was it the force from the previous question?

Reasons? I think it was good because one question led to another, letting you draw from previous answers to get the next one. I also had the Q to Q topic, which was really good, despite being historical based V_V

4 C can't be right: x falls with a horizontal velocity lower than that of y, and both have the same initial vertical velocity and acceleration. It has to be D.

Thanks, I was thinking this because the field line would just go straight through all of them at the same magnitude.

I think 5 B is right, according to F = (Gm)/(r^2) As for 9, my re3asoning was that eddy currents are formed in the thin conductor, so electrons would be concentrated around Q or S, but S was experiencing the most change in magnetic flux so more electrons would be concentrated there, due to the...

Oh you will, and if you want to check you could always lodge an application with FOI xD

I did that, but shouldn't r = 7*10^6 + (Radius of Earth)? Otherwise, I just got A for it lol xD

Mine: 1 C 2 A 3 C 4 D 5 B 6 A 7 C (looking back, it might be D) 8 C 9 D (guess) 10 B 11 D (guess, I figured the first graph should be a sine curve and the second should resemble a cosine curve) 12 C (guess, don't know what donor or acceptor levels are xD) 13 B 14 C 15 A (oh...

Hey how did you calculate 2? I couldn't find the diameter of the earth on the data sheet :(

And that includes past papers, Catholics, Independents... Gosh, so straight forward...

Me too, maths calculations is what makes physics sexy. Knowing how to apply the equations is sexier.

V_V Unfortunately, yes.