haha damn, I guess the complexity of the working will depend on the mark allocations but yeah you're right
btw after checking Keelan134's work, final answer should be 6.52 x 10^8 J, which is pretty close to my answer hahaha
Easy, W = Fd
= (200*9.8)*350000
= 6.86 x 10^8 J
Discuss Einstein's and Planck's differing views o scientific research and its place in society and politics. (4 marks)
Easy, W = Fd
= (200*9.8)*350000
= 6.86 x 10^8 J
Discuss Einstein's and Planck's differing views o scientific research and its place in society and politics. (4 marks)
Haha not trolling but pretty much the only ones im not 100% sure about are Q11f)ii),Q12d)i), Q14b)iii), and Q14ci), which is around 7 marks including the one I just lost from MC
nahh because when you group the C and L together you end up with 6 groups
i.e. O, Y, M, P, I, CL
and that^ can be arranged 6! ways but the C and L can be arranged within each other 2 ways so its D, 2 x 6!
4: If its C then the amplitude is indeed 2 but the period is 6pi, meaning it would be restricted to 3pi, not 3pi/2
5: Group the C and L together so theres 6! ways of arranging those letters but the C and L can move in between each other 2 ways, hence 2 x 6!, so D
For the bus question how did everybody do it?
I equated the work done to the kinetic energy, i.e. Fd = 0.5mv^2 and I got a reasonable answer of 15 km/h or something...not anywhere near 300's haha