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  1. MONKEYjulz

    School Attendancy

    Hey all, Was just wondering after trials if going to school is still compulsory (taking into consideration you've finished your course). Like will it add to your usual school attendance, and if it drops below a certain amount of days absent, you don't get your HSC? I heard that you must attend...
  2. MONKEYjulz

    English Paper 2: Dilemma

    The only reason it's called trials is to imitate the real HSC, and i'm pretty sure the half yearlies was the same exam length time as well. It may very between schools. No need to have a fit..please~
  3. MONKEYjulz

    English Paper 2: Dilemma

    Been in the HSC game for almost a year and doesn't even know how long a English Paper goes for. Can't blame the school for your own forgetfulness tbh
  4. MONKEYjulz

    Chemistry Success One 2007 Answer

    Yeah i knew it! thanks for the clarification
  5. MONKEYjulz

    Chemistry Success One 2007 Answer

    Hey guys, For the success one book (i got the 08 version), question 23 in the 2007 paper, is it me or is the answers wrong for it. It asks to draw/write the structural formula for ethyl hexanoate. I looked at the answers given in the back and i think they accidently added an extra carbon in...
  6. MONKEYjulz

    ***Some binomial questions***

    YES! Of course. Here's an example: nCk = nC(n-k) Let k = 2 and n = 12 12C2 = 12C(12-2) 12C2 = 12C10 which is true by calculator. The way this theorem works is because in an expansion, the coefficients are mirrored both ways from the centre of the expansion.. you'll see in the pascal triangle...
  7. MONKEYjulz

    ***Some binomial questions***

    Oops, i added x^0 and x^-0 coefficients, forgot to times em lol Cheers man
  8. MONKEYjulz

    ***Some binomial questions***

    Why did u n-k both sides? you only do it to one side... expressed in the law itself. Follow my steps written before, its clear. Also, these two lines you wrote don't make sense. You must of typo'd 12C(12-3r) = 12C(12-2+r) 12-3r = 2+r
  9. MONKEYjulz

    ***Some binomial questions***

    I did what you did and still couldn't get it.. the eff.. could u show the workin or something please
  10. MONKEYjulz

    ***Some binomial questions***

    LOL you stole my idea! =p
  11. MONKEYjulz

    ***Some binomial questions***

    I don't know if this is right. But i solved it using this method. Using the law: nCk = nC(n-k) Taking into consideration only the k bit, I went: 3r = 12 - (10 - r) which is k = n-k 3r = 2 + r 2r = 2 r = 1 Also works if you go: 12 - 3r = 10 - r Hope you understand.
  12. MONKEYjulz

    STAT Results

    150 or greater. I feel disadvantaged.. so far i'm the only one in this thread with the LOWEST STAT overall.. far out :burn:
  13. MONKEYjulz

    STAT Results

    lol i suck so bad at verbal too :( Verbal: 149 Quantitative: 161 Overal: 155 I hope the cutoff mark for Pharmacy is still 150 *crosses fingers*. It says it might be different for 2010 entry coz 150 is based on this years.
  14. MONKEYjulz

    STAT Results

    I got mine 20mins ago... quite disappointed and surprised at the same. Does anybody know if just >150 STAT score guarantee's an entry with the required UAI. Or do you have to get a REALLY good STAT score?
  15. MONKEYjulz

    Need help with explaination of Permutation Question

    If you can flip it over, then wouldn't circles be 11!/2 as well? This bracelet/necklace concept is ghai
  16. MONKEYjulz

    Need help with explaination of Permutation Question

    Twelve differently coloured beads are arranged around a necklace. How many different arrangements are possible? Is the working out: 11! / 2! If it is why? thanks
  17. MONKEYjulz

    Help with substitution

    sweet got it thanks
  18. MONKEYjulz

    Help with substitution

    Can someone please show me how to integrate: e^sqrt(x) using the substitution u = sqrt(x) Thanks
  19. MONKEYjulz

    Math Question Help :)

    Alright. Thanks man
  20. MONKEYjulz

    Math Question Help :)

    Is my solution correct? Given P(x) = 4x^3 - 27x + k has a double root. Find possible values for k. P'(x) = 12x^2 - 27 P'(x) = 0 x^2 = 27/12 x= +/- 3/2 P(3/2) = 27/2 - 81/2 + k = 0 P(-3/2) = -27/2 + 81/2 + k = 0 k = 54/2 = 27 k = -54/2 = -27 Help is appreciated.
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