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^{n}C_{2}+^{n}C_{3}=220 \; \; \; \textup{[Such notation implies}\; n\; \textup{is a non-negative integer (strictly greater than 2), however such knowledge is not requred at HSC level]} \textup{Thus:}\; \; \frac{n!}{2!\left ( n-2 \right )!}+\frac{n!}{3!\left ( n-3 \right )!}=\; \; \frac{n\left (...

This , however washing the pipette/burette with distilled water THEN the solution they will be filled with is acceptable (and the way i learnt it).

\ln \left (AC \right )=\ln \left (C/Q \right )=\ln \left ( C \right )-\ln \left ( Q \right )= \left ( \beta _{1}+\beta _{2}\ln Y_{i}+\beta _{3}\left [ \ln Y_{i} \right ]^{2} \right )-\ln \left ( Q \right )\; \;\therefore \frac{\mathrm{d} }{\mathrm{d} Y_{i}} \ln \left (AC \right )=...

Think about what you are trying to prove, now you have an integral - draw what this means. The integral you have supplied is the area between the curve 1/x and teh x-axis bounded by x=2^n and x=2^n+1 So your 'lower' bound for the integral will be the area of the rectangle with width...

According to the 2008 HSC markers (http://www.boardofstudies.nsw.edu.au/hsc_exams/hsc2008exams/pdf_doc/chemistry-notes-08.pdf, page 21), either is acceptable.

Yes, for first year MATH and STAT units, they'll help you out. Alternatively, integration/differentiation questions can be posted in the HSC Mathematcs /Extension 1 /Extension 2 forums here on BOS, as long as they are in the correct section. Plenty of people will asnwer your questions :).

Well, STAT170 is statistics, whereas MATH123 is the easiest-level Mathematics (i believe its introduction to calculus, so equivalent to 2unit HSC maths). It really depends whether you want to learn calculus or not; if you do, go for MATH123. That being said, some basic calculus may be...

Just understand the main concepts / models - Keynesian model, AD-AS model, exchange rate model, etc

Re: Chemistry HSC questions sorted topic-by-topic I just found out recently that from 2008 onwards, HSC 'Notes' from the marking centre with the marking guidlines also now come with sample solutions. Looking at the 2008 version (found here, 2009 version has not been released yet), they are...

Periodic table will help you out.

let u=secx use the fact that d/dx(secx)=secxtanx

In general: Acid + Base ---> water + salt Acid + carbonate base ----> water + CO2 + salt So you may find it useful to work backwards. so, for example, Magnesium Chloride (MgCl2), well this must have been formed from HCl and Mg(OH)2. Sodium Carbonate, well this must have been formed...

Draw a vertical line. A (straight, intersecting) line that is 75 degrees from that. either way.

One way to think about it is, it is a dilution by a factor of 10 - we know diluting an acid makes pH increase - pH is a logarithmic scale, so a 10-fold change in concentration means a 1-point change in pH. Thus, pH should increase by 1 - to 2.1+1=3.1. A more rigorous apporach would be as...

we know 7=Ux*t=U*cos(15)*t---->Ut=7sec(15)...(1) Sy=Uyt+0.5at^2 0=Usin(15)t-4.9*t^2 ---> 0=Ut(sin15)-4.9t^2...(2) we can solve this by substituting (1) in (2) which will leave us with one equation in one unknown: 0=7sec(15)(sin15)-4.9(t^2) 0=7tan15-4.9t^2 solve for t sub back in (1)...

The MathWorks Australia - MATLAB and Simulink for Technical Computing Its cheaper than normal if you are a student.

relativistic energy when stationary : E=(m_0)c^2. Realtivistic kinetic energy, as seen by a reference frame in relative motion: KE=0.5(m_v)v^2 your question is vague...

Sorry, i think the answer is (C), misread the options! From what i remember you always face up - which is the direction of motion during launch, but opposite that during re-entry.

It does not violate the principle of relativity because you have reference to an external point (outside your frame of reference).

1. Find n(NaHCO3) by using n=cv 2. Find n(H2SO4) by dividing n(NaHCO3) by 2 3. Find c(H2SO4) by using c=n/v