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then there's me from a non-selective school :(

someones keen lol

It'll be interesting to see the faces of each one of you. I don't think anyone besides istudent and QZP will recognise who I am tomorrow hehe

Well, well, well, its finally come hasn't it :)

Re: HSC 2014 4U Marathon - Advanced Level oh yes, I forgot to test that

Re: HSC 2014 4U Marathon - Advanced Level I don't know if this is correct, but here's what I did:

?

There's nothing wrong with the mark allocation for those 2 questions. For (a), 1 mark for determining the gradient and 1 for finding the correct angle. Isn't (b) worth 1 mark, like it only requires modifying the numbers to use the limit.

wait nvm its 3u, but what was the query about the paper?

alright, going to try the paper out now :)

Re: HSC 2014 4U Marathon - Advanced Level Can you give us a hint? I'm not that good with these types of questions

lol, I think carrot is jealous because I didn't ask for his

Analyse how microeconomic reforms promote structural change. (5 marks)

what's wrong with getting a signature :p

You must come so I can get a photo and signature :)

Re: MX2 Integration Marathon yes sorry my bad LOL

- Made a mistake in my first post lol

Re: MX2 Integration Marathon This is what I did when I answered it in the other marathon: http://community.boredofstudies.org/attachments/14/mathematics-extension-2/30828d1409035801-hsc-2014-4u-marathon-screen-shot-2014-08-26-4.48.33-pm.png

Re: MX2 Integration Marathon If divide top and bottom by n^2, we obtain a Riemann's sum for approximating the area beneath the curve y=1/(x^2+x+1) in the interval 0≤x≤1. Since f(x) is decreasing in that interval, B represents the sum of 'n' upper rectangles and A represents the sum of 'n' lower...

Re: HSC 2014 4U Marathon That's correct, good job :). It's a cool result since it ties in with the golden ratio (Kepler Triangle)