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Re: another question 2cos2x = cosx - sinx solve for 0<=x<=360

the flow of water into a small dam over the course of a year varies with time and is approximated by dW / dt = 1.2 - cos^2 pi/12t, where W is the volume of the water in the dam, measured in thousands of cubic metres, and t is the time measured in months from the beginning of jannuary. What is...

Re: another question cbf man >< its too hard to read, latex better just go wolfram if you want the solution

Re: another question i like :jump: i dont like :hat:

split cos^2x 2x into cos 2x . cos2x product rule did anyone do it another way?

sinx = 2/3 cosx = root 5/3 cosy = 3/4 siny = root 7 /4 sin(x+y) = sinxcosy + sinycosx

Re: another question i'll let 011er's answer this if not done by 6 then ill do it, then merlin time :)

Re: another question i did it diff way but same answer :D Let X be on AP such that AX = 2cm PQ^2 = 17^2 - 8^2 PQ = 15

| x + a | + | x + b | =sqrt (x+a)^2 + root (x+b)^2 = (x+a)^2 > 0 and (x+b)^2>0 x+a > 0 and x+b > 0 x> - a , x> -b condition : a =/= b since = (x+a)^2 > 0 and (x+b)^2>0 | x + a | + | x + b | > 0 if wrong clue me

ehhh how you get R = root 1+3 i thought a = root 6 b = root 2 R = root (6+2) i'm lost :spin: link me to some tutorial site so i can learn how to deal with the (2x) part maybe

Explain carefully why | x + a | + | x + b | (for some a =/= b) is always strictly positive. assume | x + a | > 0 | x + b | > 0 for some a =/= b a =/= b =/=0 , as well as all real values, | a | =/= | b | since | x + a | > 0 , | a | =/= 0 therefore | x + a | > 0 is true...

can show me the formulas of how you do this xD or just private message me with the long steps i kinda forgot prelims :o

let\ u = cosx\\ du = -sinxdx\\ x = \pi , u=-1\\ x=0, u = 1\\ \int_{-1}^{1} u ^2du\\ I = 2/3\\ this is integrating trig functions, more of yr 12. which topic do you want me to post a question on, i'll do it after i watch tv :P

yes it is prelim. It is called implicit

x^3 + y^3 - 3axy = 0\\ x^3 +y^3 - 3xy = 0\\ d\dx (x^3 +y^3 - 3xy) \\ =3x^2 + 3y^2 y' - 3y - 3y'x\\ y' = \frac {y-x^2}{y^2-x}

just this : pray to ullah

tan(2x+x) = \frac {tan2x+tanx}{1-tan2xtanx}\\ = \frac{\frac {2tanx}{1-tan^2x} + tanx}{1-tanx\frac {2tanx}{1-tan^2x}}\\ = \frac {3tanx}{1-tan^2x-2tan^2x}\\ = \frac{3tanx}{1-3tan^2x}\\ for those who dont know how to get tan3x exploitable's method is perfectly valid from the end of LHS, times...

there was someone on the news who was in yr 7 or so and finished secondary studies, going into uni. check it out. i covered 3 modules within 3 weeks, and now i've forgot most after 2 terms :< experiment on your child xD A = Average B = Bad C = Crap D = Dead E = Ended F = FU*KD

Discuss the value of Hamlet's delay for action, and the value it has for the modern reader. (TEXTUAL INTEGRITY) Dot point form will be fine, just want a brain storm so i can link all my ideas together. any synthesis will be more appreciated :music:

It acts as an instructive device which provides a basis of awareness for the reader. Furthermore, it functions as a mechanism which is intensified by the excesses of enlightenment, sub conscious, duty and the universal dogma. bla bla bla...just reveals the mediocrity of men through...