5b I had amplitude=2/3 and period t= 2pi/3
5c all angles
TPM = KPL (vertically opposite)
TPM=PQM (angle in the alternate segment)
PQM=KLP (exterior angle to a cyclic quad = interior opposite) or (PLK=180-PQK=PQM)
therefore TPM=KPL=PQM=PLK
therefore KLP is isocele (base angles of isos...