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Marry me? Thanks so much =D Edit; more questions possibly coming soon ._.

If logb2 = 0.6 and logb3 = 1.2, find: a) logb6b b) logb8 c) logb1.5b² The "b" in "logb" is subscript. Most of the logarithm stuff we've done in class has gone way over my head, I'm really lost. Thanks in advance!

Oh hell yeah, the actual lecture was incredibly boring.

Today at 2:00pm, a physics lecture was held at a university (I forget which one). The lecture was broadcasted through a live large-scale webcam system in which schools could tune in. The schools also had their own webcam system where they could view, listen and talk back to the lecturer. It was...

∫(3^x) dx It's probably some simple rule I missed out on. Thanks in advance!

More library book privileges. You must feel special.

Anger management. @OP; take notes furiously, even if they don't make sense or are irrelevant. Usually it's easier to keep on a roll in class.

Little mistake there Aerath; 3 = 4 - 8 + c 3 = -4 + c c = 7 eq: 4x² - 8x + 7 The rest is all good =]

First, is there a maximum amount of points a course can raise each year for cut-offs? Second, how well do I need to do in; Ext1 Eng Adv Eng Ext1 Maths Adv Maths Chemistry Physics To achieve ~94? My school is ranked about 50th, if that helps. Thanks in advance =]

@Aerath: Thanks so much for writing/scanning/uploading etc, its so helpful to see how things are drawn out and calculated. @lolokay: Sweet, now I can commit the formula to memory. Also thanks for your help in the other thread ;]

Could someone write the formula for finding Volume with Simpson's Rule? I can see pi*(h/3)[y0^2 +( ______ )+ y2^2]

Sweet, thanks =]. Edited.

f''(x) = 5x^4 f'(x) = x^5 + C f'(0) = (0)^5 + C = 3 .'. C = 3 f(x) = (x^6)/6 + 3x + D f(-1) = [(-1)^6/6] + 3(-1) + D = 1 1/6 - 3 + D = 1 D = 3/5/6 .'. equation = (x^6)/6 + 3x + 3/5/6 f(2) = [(2^6)/6] + 3(2) + 3/5/6 = 20/1/2

Both are right - is the formula for volume just pi*simpson's rule? I don't quite understand what you did after 'Integrate both sides' ='[

Wait, I think I was wrong. Let me try it out.

It tells you that y' = 0, (thats what the dy/dx thing means) so C must be 0.

Just a bit hazy on this one =[ The curve y=2^x is rotated about the x-axis between x = 1 and x = 2. Use Simpson's rule with 3 function values to find an approximation of the volume of the solid formed, correct to 3 significant figures. Also, if you're bored; Find: ∫ [(x+2)/√(x+3)]dx For...

For y' = root(x) y' = x^{1/2} y = \frac{x^{3/2}}{3/2} y = \frac{2x\sqrt{x}}{3}

Epic burn.

I've seen a lot of posts regarding the importance of ranks within a school, and how they contribute to your HSC mark. My question is, why do the ranks matter within the school? What if your year was very smart and your rank was only mid-range, whilst you could have a very high rank in a...