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  1. S

    Exact Values...

    Yeah gotcha. Sure... Will be doing.
  2. S

    Values of x - By differentiating :D

    I'm sorry.... I meant it just to be (cot25 + tan65)/ cot25 ... = 2. I'll keep this in mind for next time. :)
  3. S

    Values of x - By differentiating :D

    Good, which = 2. I'm right aren't I? :) See my post at 3.07pm - is that right?
  4. S

    Values of x - By differentiating :D

    oh, i'm not sure. I thought that if I just replaced both cot25 with tan65 (for the reason we both know they're the same) so it would be tan65 + tan65 / tan 65.
  5. S

    Values of x - By differentiating :D

    Yeah ok then. Thanks for the consideration... Unfortunately I don't have the answers. :L
  6. S

    Values of x - By differentiating :D

    Parvee (if you're still there)... I think I have got it... cot25 = tan65 (same reason as what you gave - Cot(theta) = tan(90 - theta) So tan 65 + tan65/ cot 25 Then we can replace the bottom with tan65 So 2tan65/ tan65 = 2 (because the tan65) cancel out! :)
  7. S

    Values of x - By differentiating :D

    Thanks... Unfortunately I don't have the answers... It's a question from a past paper. If I do it on the calculator I get two??? But not sure if this is right.... :)
  8. S

    Values of x - By differentiating :D

    Thanks again... Yes I just realised that... Sorry... And then I posted at the same time as you.
  9. S

    Values of x - By differentiating :D

    Yes, I see. I had done +1 instead of -1, thanks for your continued help. :) This is a different topic but....How do I do the below? I am sure there is a way that doesn't involve using a calculator. Am I right? Simplify a) tan 70(deg) + cot 20(deg) - 2tan70(deg) b) cot25 + tan65 / cot25...
  10. S

    Values of x - By differentiating :D

    Thanks all for your assistance. (and even two moderators!) :):)
  11. S

    Values of x - By differentiating :D

    I got x = -2 and 3/2... from x= -1 + - root 49 / 4.... ==> x = -2, 3/2 This right or not? :)
  12. S

    Values of x - By differentiating :D

    So y'= -4(4x + 1)^-2.... This right?
  13. S

    Values of x - By differentiating :D

    Hello All... Could someone please help me with this question...:) Q. For what value of x does the functions have y = 1/4x -1 have y'= -4/49 __________________________________________________ (Sorry I can't work Latex - This what I tried to do in Latex [tex]$y = lim h$...
  14. S

    Linear Functions Help D:

    Very good... No worries al all. :D
  15. S

    First principle

    Thanks. :) Have you completed Task #3 for Yr 11?
  16. S

    First principle

    Thanks again (I can see it now), the time you have taken to help me is enormous. I hope you have great success over the next year and a bit.
  17. S

    First principle

    Thanks heaps but I don't know why I can't see it (again!!)... Could you possible change it like you did yesterday? Please? Sorry to have to do this...:(
  18. S

    Part of Differentiating...:D

    Dist QU: Root 10/9 Dist PU: Root 10 So 1/2 x Root 10/9 x Root 10 = 1 2/3 ... I believe this is right now? :)
  19. S

    Part of Differentiating...:D

    No worries at all. ;D Thanks a million. :)
  20. S

    Part of Differentiating...:D

    Appreciate your help cookiez69 - +1 to your rep. :)
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