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let me know if its right or wrong ^^

I was thinking the same thing

before I write the reduction equation is the net ionic equation: Mg + 2H+ +2Cl -1 -> Mg2+ + 2Cl- + 2H+ + O2-

Okay so here's another problem I found: for the following reaction : Aluminium with sulfuric acid - when writing the reduction equation, why do we only o this for hydrogen gas and disregard the sulfuric acid

Feel free to post more examples guys :D OR practice questions that I can do thnx

Thankyou again for the help! How to you know though if an atom is neutral ? And is it true metals oxidise first

If you split these into the half (redox) equations you get: Cl2 + 2e- ---> 2Cl- 2Br- ---> Br2 + 2e- So what is happening in these redox equations. Like why is 2CL- on the right hand side and 2Br- on the left

thankyou, I get it!! It's okay I like in depth explanations:)

ohh okay. does does Cl- have the minus next to it because it has to lose 1 electron to gain an full shell

"From here it can be seen that the H+ ions are spectator ions, so the net ionic equation is: Cl2+ 2Br- ---> 2Cl- + Br2" - What are spectator ions??? - Why does Cl- have the minus next to it (is that because it has to lose 1 electron to gain an full shell) - Also so an ionic equation is...

Okay, I am a bit confused on how to write redox and oxidisation equations. Also from this , how to identify which substance is the oxidising agent or reducing agent. Can someone please go through an example and steps required. Thanks!

152 cm :/

oh okay , i'll check it out

thankyou so much InteGrand :) yes that first question did have a typo in it btw: what did you use to type up your answers?

Okay so I may have to type these questions out again since the photo just won't open. Factorise fully" Q.1. (a^2-b^2-c^2)^2 - 4b^2c^2 ANS: (a-b-c)(a+b+c)(a-b+c)(a+b-c) Q.2. (ax+by)^2+(ay-bx)^2+c^2(x^2+y^2) ANS: (X^2+Y^2)(a^2+b^2+c^2) Q3. ( a^4+a^2+b^2+b^4) ANS: (a^2 -...

I realised that, but I knew it was just a mistake. I'll re-upload the photo again

Also need help with factoring the 1st, 2nd, and last questions in the image above (it upside down). thankyou

Thanks ! I see what I did wrong, silly mistakes

To fully factorise 4x^4 -2x^3y-3xy^3-9y^4 I got ( 2x^2+3y^2)(2x^2-3y^2) -Xy The answer is : (2x^2+3y^2)(2x-3y)(x+y)

Another question in exercise 1C question 8d. I don't get the answer