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for those that care, the torque on a rectangular coil consisting of N loops is given by: T = NIABcos@ here we have a cos@ factor, not a sin@ like we do in the force formula (you should be able to derive this equation). the magnetic field exerts a force on the vertical sections of...

u = sec x u' = (sec x)(tan x) v = tan x v' = (sec x)^2 Int (sec x)^3 dx = (sec x)(tan x) - Int (sec x)(tan x)^2 dx Int (sec x)^3 dx = (sec x)(tan x) - Int (sec x)[(sec x)^2 - 1] dx Int (sec x)^3 dx = (sec x)(tan x) - Int (sec x)^3 dx + Int sec x dx 2 Int (sec x)^3 dx = (sec x)(tan...

let AB = x, BC = y, angle CAB = @ dx/dt = 0.1 -----(1) from trig: x/10 = cos@ x = 10cos@ dx/d@ = -10sin@ -----(2) using (1) and (2): dx/dt . d@/dx = 0.1 (-1/10sin@) d@/dt = -1/(100sin@) when triangle is isosceles, @ = pi/4: d@/dt = -1/[100sin(pi/4)]...

Int x. [root(x+1)] dx dx = 2u du u = root(x+1) Int [(u^2)-1]. u 2u du Int 2u^3 - 2u^2 du u^4/2 - 2u^3/3 + C (x+1)^2/2 - 2(x+1)^(3/2)/3 + C

let roots of f(x) = ax^2 + bx + c be A and B A + B = -b/a AB = c/a a) when A = 1/B, c/a = 1 c = a b) when A = -B, -b/a = 0 b = 0 c) when A = 0, c/a = 0 c = 0

total length 10m equals the perimeters of the square and rectangle: 10 = 6x + 2y ------(1) total area is given by: Atotal = x^2 + xy sub (1): Atotal(x) = x^2 + x(5 - 3x) = 5x - 2x^2 we now differentiate to find the value of x for which Atotal(x) is a maximum: Atotal'(x) = 5 - 4x...

another quality post from jordanfaggot22 :lol: kekekeke

stop posting jordan, no one likes you

F = Gm1m2/d^2 F = 8*10^-8 G = 6.67*10^-11 m1 = 10 d = 0.4 sub into equation and solve for m2 the centripetal force is equal to the gravitational force: F = Gm1m2/d^2 G = 6.67*10^-11 m1 = 10^30 m2 = 10^22 d = 3*10^12 sub into equation to find F to find the period we need the...

dude whats wrong with this guy...

they didnt build the thing then go "so what next guys?"

dude seriously, no offence but you've got no idea. if you want to argue for dr. kent at least post his paper / link to his calculations.

another way you could do it is if you knew its less than zeta(2) = pi^2/6 1 + 1/2^2 + ... + 1/n^2 + ... = pi^2/6 < 1.99 1 + 1/2^2 + ... + 1/5^2 > 1.45 .'. 1.45 < 1 + 1/2^2 + 1/3^2 + ...+1/99^2 < 1.99

derive the two equations: Sy = uyt - 9.8 t^2/2 -----(1) Sx = uxt -----(2) from (1): - 3 = - 9.8 t^2/2 t ~ 0.78sec sub into (2): R = 800 x 0.78 ~ 626m

gg musk

im not asian, monkey

um wot?

monkey

shut up idiot, stop talking to me. i dont talk to monkeys