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YAYER SOLVED IT MYSELF LOL now changing the question around how do you find the point where the tangent touches the circle now thats idno xD

question unsolved :cry:

<DIR>find the exact length of the tangent from (4, - 5) to the circle x^2 + 4x + y^2 - 2y - 11 = 0 </DIR>next

Moving on to the next question A point P(x, y ) moves in the XY - plane such that its perp distance to the line 2x - y +5 = 0 is equal to its perp distance to the line 2x + 4y - 7 = 0. Find the path of P and describe how it is related to the given lines. Locus questions preferred over sequence...

|ax + bx + c| / (root a^2 + b^2) ------> perp distance form sub in a b c relatively and x as the centre of the circle, thus obtaining a distance which = 5. Since the circle has radius = 5, it is therefore a tangent. As for your method, it is extremely tedious to make LHS = RHS Nevertheless i...

clue : use perp distance formula to prove it has same distance as radius

simply state it is a circle with radius 3 i guess now my question prove that the line 3x+4y+21 = 0 is a tangent to the circle x² - 8x + y² +4y-5 = 0 should not be hard

Heya this is a thread where anyone can post difficult, regular or extremely challenging questions from the locus, parabola, sequence and series topic. This thread was started because i have a test on friday and hopefully i can revise on 2u topics which i did last year xDD Thanks and much...

this is 3u factor theorem, not even really 4u, but used in 4u :hammer:

wtf is this O_O has it been removed from the new syllabus? never encountered any such question i dont even really wna read the working out cos its so long xD

answer that one please xDD

thx but for the first one how'd you know it = (x^2+2x-4)(x^2+2x+5)=0 on the first step??

Solve the equation x^4 + 4x^3 + 5x^2 + 2x - 20 = 0 If the equation x^3 + 3px + q = 0 has double root for p< 0 and q>0, prove that q^2 + 4p^3 = 0 many thanks :rolleyes:

dw found out myself :D

bump...

bump....

if something has roots a , b , & whats the general formula for a^3 + b^3 + &^3 sorry i forgot ><

ahh i see got ya you can do it :L i have work to do :uhoh::uhoh::uhoh::uhoh::uhoh::uhoh::uhoh:

if asymptotes are y = +-x how can parallel lines cut each other? :p

quick question can explain what formula you use etc. \cos 3\ominus = \frac{1}{2} find the roots how do you space and enter on latex?