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tan(30) = 1/sqrt(3)= opp/adj = rise/run Setting the origin at the cliff the slope is given by (1/sqrt(3))*x -50 = y The motion of the projectile is given by (-g*x^2)/100 + x = y Solve for x: (1/sqrt(3))*x -50 = (-g*x^2)/100 + x By applying the quadratic formula you will answer. Remember...

For q1 the upper bound doesn't matter as the derivative of a constant is zero. So an equivalent question is: - d/dx integral (2x^5-3)^6 dx As differentiation and integration are inverse operations the result is -(2x^5-3)^6 For q2 try the substitution 6sin(u) = x You can then use the...

Need more terms. However, it is clear the series is not arithmetic or geometric.

We know from the special ratios sin(60) = sqrt(3)/2 Sine is defined on the unit circle as sin theta = y. The obtuse angle is 120 as the related angle of 120 is 60 degrees. Note that sine is positive in the second quadrant(ASTC). sin(120*2) = sin(240). The related angle of 240 degrees is 60...

As Haruto mention tan pi/2 is undefined. This because of the definition. The definitions of trigonometric function from the unit circle are: tan theta = y/x (At pi/2, y = 1, x=0 therefore tan(pi/2) = 1/0 ) cos theta = x sin theta = y

I think I got it now. The lower quartile is referring to 25% (as in Q1 from box plot) and the upper quartile is referring to 75%(Q3). As Imaiyuki mentioned 1 standard deviation within the mean is approximately 68% of the data. Divide by 2 => 34% of data is above the mean and 34% below the...

B) As the upper quartile is 76 and lower quartile 64

Going by "yorkyorkxp" it looks like commenting wouldn't be considered apart of intrinsic documentation but internal documentation

Mainly just know how to differentiate. Make sure you are able to solve word-problems e.g. maximising area enclosed by a fence, maximise the volume of a cardboard box etc. Make sure to communicate your working out correctly. Make sure you know to determine the concavity of a curve using the...

Using the result of 11a) you can find sin A cos A = 23/32. This means 23 is the adjacent side and hypotenuse is 32 units long. Using Pythagoras theorem you can then find the value of the opposite side. Alternatively, you could use sin^theta + cos^2 theta = 1. I am assuming you have done...

The size is given in bytes. Each variable size is given in bytes. So if take you the ASCII code you will see each character is 1 byte e.g. 0000000 contains 8 bits as there are 8 binary digits. This is equivalent to 1 byte as 8 bits = 1 byte. Each record contains 10+ 8+ 5 + 4 Bytes. There...

Thank you

x = 4*cos(theta) - sin(theta) Use the theorem: cos(theta + phi) = cos(theta)*cos(phi) - sin(theta)*sin(phi) => r*cos(theta + phi) = r*cos(theta)*cos(phi) - r*sin(theta)*sin(phi) Equate x = r*cos(theta)*cos(phi) - r*sin(theta)*sin(phi) => r*cos(phi) = 4, r*sin(phi) =1 Therefore...

lim x->0^+ (1/x + a) = infinity lim x-> 0^- (-x+a) = a Therefore there is no value of "a" that makes the function continuous as the left and right one-sided limits are different.

If by, pass you mean swap then C requires only one swap, not two. Take a look at the original array. D, on the other hand, requires 2 swaps.

I did 8 quotes for each essay, but I am not sure how many quotes you should aim for? You should find the marking criteria on NESA past HSC exams if you need.

The degree does not exist. If you are interested in doing B Eng (Hons) B Computer Science from UTS it might be best to contact someone. That way you can get an idea of how many points are for recognition of prior learning. You can see there is no B engineering B Computer Science degree by...

Q1. let women be A and B case 1: A is on the committee 6C2 case 2: B is on the committee 6C2 case 3: neither A, B is on the committee 6C3 7C4( 6C2 + 6C2 + 6C3) = 1750 Q2. 8*6/2! = 24 (8 options at first, since can't consider the point opposite there then 6 options. Divide by 2! as...

For an English essay, without the example, there is no explanation that can be given. So : Point Explanation (No explanation is possible without the example) Example Link will not work. _____________ But: Point Example Explanation Link will work. As such, there is no...

I think this question involves hypergeometric distribution as number cards decease by 1 as each is dealt. i.e. P(?AAAA) = 48/52 * 4/51 * 3/50 * 2/49 * 1/48 Maybe you could consider the cases: ?AAAA, A?AAA, AA?AA, AAA?A, AAAA? and find the probability that way. i.e. Find the value of...