Search results

co-sign :D

^Yup, given the information, you can only assume that the equilibrium is x=b (where b is any integer), so the equation of motion would be x = b +Asin(nt + α). Since you are only given two pieces of information, I'm not sure you can solve for the period and amplitude...I could be wrong though.

bump

Can't stand castle hill, too noisy.

yes but if you look at my original post you'll see what I was referring to lol

\int x^2e^{2x} dx is in the form of f'(x)e^f(x) ????? Am I blind or something?

Nope. that wasn't in the form of f'(x)e^f(x)

How exactly can you do that with 2u knowledge?

Exactly how you do it.

9. The chord forms an isosceles triangle with the centre (since it is the radius), so you can find all angles in the triangle (base angles of isoceles triangle are equal and angle sum of triangle is 180). You can then use the sine rule to find the radius plug that into the formula for arc...

You owe them $98, of which you have $1, so you minus the $1 not add it...

you mean 1 of the LHS = 2 of the RHS Your line 6 is wrong.

^ can you show that?

Re: HSC 2012 Marathon :) Are we assuming the ball is a perfect circle?

Re: HSC 2012 Marathon :) Is it in the 4 unit course?

Correct.

Re: HSC 2012 Marathon :) How can you take the discriminant for a polynomial of degree 3?

Re: HSC 2012 Marathon :) $Let the roots be $\alpha , \frac{1}{\alpha }$ and $\beta \\ $i) Using product of roots,$\\ -b= \frac{\alpha }{\alpha }\cdot \beta \\ \therefore \beta = -b\\ $ii) Sum of roots two at a time,$ \\ 1+\frac{-b}{\alpha }-b\alpha = 0 \\ $dividing by b $\Rightarrow...

lol. you can't solve this without a third equation, and even if you were given one, this is not general maths level. Your teacher is retarded

Re: HSC 2012 Marathon :) Wouldn't that be u = 1/sqrt(x) ?