P=I^2 x R
P=2^2 x 4
P=4 x 4
P=16 Watts
to calculate voltage in the 4 ohm resistor
V=IR
V=2 x 4
V= 8 volts
Then use this 8 volts in P=V^2/R
P=8^2/4
P=64/4
P=16 Watts
therefore by using both equations you get 16 watts.
:uhoh:
:D
Re: maths help needed ASAP
Domain: 0 <= x <= 360
tan(x-60)= -sqrt 3
(x-60)= -60, 120, 300
x= 0, 180, 360
This question is explained below:
line 1: question
line 2: tan^-1 both sides to get -60, 120 and 300
line 3: +60 to both sides
Re: maths
For the people who didn't know what lyounamu was doing, here is an explanation:
Line 1: The question
Line 2: Cos^-1 both sides to get solutions 60, 300, 420, 660, 780
Line 3: -60 to both sides
Line 4: Divide by 2 on both sides
Energy(J)=Power(W) x Time(s)
E=(100 + 50) x (2days x 24hours x 60mins x 60seconds)
E=(150) x (172800)
E=25920000 Joules
E=25920 kJ
E=25.92 MJ
For the 2nd question i don't know.
If you do really well in bst, you won't get scaled down, unless your class scales you down. You should aim for at least in the 90's for all of your subjects. Keep extension, and try really hard, you could get your UAI.