hey sorry to ask a pretty silly question but:
is there a theorem or somehting i should no about the intersectionof the altitudes in a triangle from each vertices
will they always all intersect at the same point?
cause im doin a question and i proved it showing the intersection of all three...
yeah they are
its just a different form of the cos2x and stuff
u just let sinx=sin(x/2+x/2)
then use the result we know of sin(A+B)=sinAcosB+cosAsinB
to get 2sinx/2cosx/2
and cos(A+B) is cosAcosB-sinAsinB
and i cant be bothered doin the tan one
yes its in the syllabus
its just like
cos2x = cos(x+x) = cos<sup>2</sup>x - sin<sup>2</sup>
then by rearannging it u get 2cos<sup>2</sup>x - 1
but his just used cos(x/2+x/2)
surely u know this conics?
回复: Trig Problem
its not as hard as it looks
people are probably just gettin confused by the bearings?
the angle subtended at the foot of the pole is 53 +(360 -342) = 71
then just used the cos rule with one of the other sides of the triangle htan64 and the other htan69.
so u end up with...
回复: Trig!!!!!
cos<sup>2</sup>x - sinx = -1
(1 - sin<sup>2</sup>x) - sinx = -1
-sin<sup>2</sup>x - sinx +2=0
sin<sup>2</sup>x + sinx - 2=0
(sinx+2)(sinx-1)=0
sinx=-2, sinx= 1
no solutions for the first one, x=pi/2 for the second one
therefore x=2
hey can someone show me how to find the general solutions of sin x + cos x =1?
i got x= npi and x=2npi +/- pi/2
but the answer in x=2npi and x=2npi + pi/2
thanks