Should I make a new thread? Might as well.
a\alpha + b\alpha + c = 0, where\, a, b, c \in \Re \, and \, \alpha \,\in \, \Im.\, Use\, the\, results \,in\, question\, 4\, to\, show\, that \, a\left ( \bar{\alpha }^{2} \right )+b\bar{\alpha } +c=0
The results in Question 4 are basically...