Given that:
z^n + z^{-n} = 2cos{n\theta}
Where z = cos{\theta} + sin{\theta}
Show that:
4cos{\theta}cos{2\theta}cos{3\theta} = 1 + cos{2\theta} + cos{4\theta} + cos{6\theta}
This was from a past half yearly paper from my school.
English Advanced - Finished AOS, just started module A.
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