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I apologise also, how clumsy. Well integrate from a->0 + 0->-a

f(-x)=-(x^3)=-f(x). Therefore rotational symmetry about origin, hence A=0.

Fuck i hate Ellen.

Shit, that's nice. I wouldn't have seen that lol I would have done the whole: Discriminant=>sqaure root of a+ib => Quadratic formula LOL noob.

-Last intake of B engineering this year, yes this doesn't relate to OP though. -Melbourne's first year is also common (Eng Syst Design 1, Maths (diff levels), Science (elective) and Breadth (different i suppose). -I think there last year (monash and Melb) are pretty similar. Doesn't really...

Chicky pie or how ever you spell it, is still ahead i believe.

P.S: I'm not thinking about doing it, i'm just curious about it. It's pretty interesting i think.

Yeah i knew Divinci did, i think Einstein did aswell, might not have been him but some other polymath.

New program as of last week: German Volume Training. Rest Between sets: 1 min ONLY! Which i hear is the best for hypertrophy. Not so much Strength which is >=2mins, but muscle recruitment. Yesterday: (chest) Forward Dumbrell Raises: 3 x 10 reps (15.1kg each arm) Shoulder Press: 3 x...

[CENTER] Source: Uberman's sleep schedule || kuro5hin.org Anybody here tried it/do it? Was wondering if it really works and any other information on it

LOL great title and great results...free bump:D

Congratulations on some amazing achievements.

My school marked incredibly harsh. For Trial, i got 55% and topped the exam (Final Rank: 1st). I would think that would correlate to a HSC mark of 72-73 perhaps? I got 87 HSC mark for Std English. It was a joke. I did almost nothing in english all year because i thought i was terrible, getting...

Well i just got back from a thai restaurant haha we both got what we wanted

Ahh yeah ofcourse, well done man.

Thai food :o

Just jump on wearing dark sunglasses and pretend to be asleep. Legally they can't wake you or touch you /thread haha

For n=1, d/dx (x^-1)=-x^-2 n=2, d^2/dx^2 (x^-1)=2x^-3=2.1.x^-3 n=3, d^3/dx^3 (x^-1)=-6x^-4=-(3.2.1)x^-4 where d^3/dx^3 notates the 3rd derivative of (x^-1) n=4, d^4/dx^4 (x^-1)=24x^-5=4.3.2.1x^-5 ... n=n, d^n/dx^n (x^-1)= [(-1)^n.n!]/(x^(n+1)] Seems pretty obvious just via...

Alternative Method: - Rationalise denominator => Partial Fractions. Haven't checked if it works yet, but i think it would work out alright.

Hmm well from this year onwards, that is the only option at UoM, since they are dismissing the B Engineering system, to my great disgust (I'm the last intake). But yes, if you are not completely sure then BSci would be perfect as it can lead to so many different streams (e.g. Mathematical...