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oh god thats not the question at all ^, sorry bro i'm a gronk of massive proportions i shouldve said year 11 book anyway heres the question sorry it took me ages, i used the equation thing for the first time \frac{a^4-b^4}{a^2-2ab+b^2}\times \frac{a^3-b^3}{a^2b+b^3} \times...

can someone please show me how to do Q15 Exercise 1E from the cambridge 3u book

How many hours in general per night or per week do you think are needed to be getting a rank around the top 5 out of 40 students? also how do you approach the subject in terms of studying and revising and all?

yeah same here 85 and above i'd be pretty happy i think it scales pretty shit don't take my word for it but i would guess like an 83 or something would get you there

was going through the hsc timetable and saw there are 2 english advanced papers. Wtf someone explain, i had no idea we have to sit two exams.

hey you blokes finished the whole course or?

thanks everyone yeah 37 was the answer

Thanks bro, could you help us with this one as well Two skaters, one of mass 60kg and the other 95kg stand together at rest on the ice rink. The first person (60kg) pushes himself away from the other so that he is travelling at 5m/s. Find the velocity of the second person after the push.

sweet cheers. Do you have any idea with the other one?

also Two skaters, one of mass 60kg and the other 95kg stand together at rest on the ice rink. The first person (60kg) pushes himself away from the other so that he is travelling at 5m/s. Find the velocity of the second person after the push.

A force of 16n acts for 3.6 sec on an object of mass 8.35kg with an initial velocity of 30m/s. If the force acts in the same direction as the initial velocity, what would the objects new velocity be?

Who wants to help me with a question A force of 16n acts for 3.6 sec on an object of mass 8.35kg with an initial velocity of 30m/s. If the force acts in the same direction as the initial velocity, what would the objects new velocity be?

I'm stuck on these and could really use some help http://www.boardofstudies.nsw.edu.au/hsc_exams/hsc2000exams/hsc00_maths/96MAT3U.PDF - Question 2c...

Anyone besides normanhurst boys do it?

Calculate the difference in height between the two points, then calculate the difference in length between the 2 points and divide. So lets say you have a rise of 100m and a run of 1000m. It means the gradient is 100/1000, but the numerator must be 1 so that would equate to 1/10, or 1:10. It...

hey how do you know me?