Hey all,
Was just wondering after trials if going to school is still compulsory (taking into consideration you've finished your course). Like will it add to your usual school attendance, and if it drops below a certain amount of days absent, you don't get your HSC?
I heard that you must attend...
The only reason it's called trials is to imitate the real HSC, and i'm pretty sure the half yearlies was the same exam length time as well. It may very between schools. No need to have a fit..please~
Hey guys,
For the success one book (i got the 08 version), question 23 in the 2007 paper, is it me or is the answers wrong for it.
It asks to draw/write the structural formula for ethyl hexanoate.
I looked at the answers given in the back and i think they accidently added an extra carbon in...
YES! Of course.
Here's an example:
nCk = nC(n-k)
Let k = 2 and n = 12
12C2 = 12C(12-2)
12C2 = 12C10 which is true by calculator.
The way this theorem works is because in an expansion, the coefficients are mirrored both ways from the centre of the expansion.. you'll see in the pascal triangle...
Why did u n-k both sides? you only do it to one side... expressed in the law itself.
Follow my steps written before, its clear.
Also, these two lines you wrote don't make sense. You must of typo'd
12C(12-3r) = 12C(12-2+r)
12-3r = 2+r
I don't know if this is right. But i solved it using this method.
Using the law: nCk = nC(n-k)
Taking into consideration only the k bit, I went:
3r = 12 - (10 - r) which is k = n-k
3r = 2 + r
2r = 2
r = 1
Also works if you go:
12 - 3r = 10 - r
Hope you understand.
lol i suck so bad at verbal too :(
Verbal: 149
Quantitative: 161
Overal: 155
I hope the cutoff mark for Pharmacy is still 150 *crosses fingers*. It says it might be different for 2010 entry coz 150 is based on this years.
I got mine 20mins ago... quite disappointed and surprised at the same.
Does anybody know if just >150 STAT score guarantee's an entry with the required UAI. Or do you have to get a REALLY good STAT score?
Twelve differently coloured beads are arranged around a necklace. How many different arrangements are possible?
Is the working out: 11! / 2!
If it is why?
thanks
Is my solution correct?
Given P(x) = 4x^3 - 27x + k has a double root. Find possible values for k.
P'(x) = 12x^2 - 27
P'(x) = 0
x^2 = 27/12
x= +/- 3/2
P(3/2) = 27/2 - 81/2 + k = 0
P(-3/2) = -27/2 + 81/2 + k = 0
k = 54/2 = 27
k = -54/2 = -27
Help is appreciated.