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You can go on further to say that its a = -1(2x+3) and so is in the form -n²x

letting u=sinx and noting that du/dx = cosx, the integral of sin²xcosx simply becomes the integral of u² du which is easily integrated.

Youd have to think about it very carefully if you get 47 and want to repeat. Although you may know the content, you have to re-do all the assessments which means, one slip and your gone. If on the other hand you think you can get 95%+ (i.e. maintain an almost flawless performance throught the...

Yep, 47/50 and above. Id say 46 even if you plan on keeping 2u/3u. My friend who got 47 is repeating though namely because his more than capable of getting at least 48 this year (rank 1/50ish). But if you get 47, youd be stupid to do it again. Its just too much effort just to get 48/50 or dare i...

Hey nike33 what kinda text book are you using? :p

Im repeating 3u this year. Last year, i came 16th or 17th/56 which meant i had a lousy assessment mark (bloody year 12s). So far this year, im 4th and people usually do alot better the second time so fingers crossed for a 95% mark and above.

See how you go in the HSC first. You have to realise that 3u is supposed to be harder than 2u so naturally, your raw marks would be lower. Who knows, you may find that your performing equally well (relatively speaking) in both 2u and 3u and so your final HSC marks would reflect your performance...

Reminds me of the fortstreet 2003 4u trial.

Dont you love it when that happens? Shuts them up :D

Yeah, it should be K < 1 still doesnt change much . (0.12^2/.06^2) = 4... It doesnt really matter though since either way, itll favour the 2HI side. Changing the direction of the equation reciprocates the equilibrium constant so you end up with the same answer.

Youve pretty much described most of the 2unit course :p Series is alright, easy marks.

You could drop an object between two light gates and use a data logger to determine the acceleration or let an object attached to a ticker timer fall and measure the change in speed for say, each successive 5 dots (1/10th of a second).

we havent finished the course yet either. Thats alot of maths!:eek: Lets see... 1 hour lessons on tuesday and friday afternoons = 2 hours a week for 4u lessons.

Term 4 of last year.

Teachers set Focus 4 as part of an assessment so we'll be starting Focus 5 of Industrial Chem next week.

This is only true when the centre of motion is at the origin. i.e. acceleration is -n²x and not -n²(x-a)

Im pretty sure the raw marks for a band 6 wouldve been in the mid 90s. Taking into account silly mistakes and one very stupid one in the series question last year, i wouldve got about 90ish/120 and yet my exam mark was 94.

Im DOING IT :D (funny film) Q: 4 moles of hydrogen iodide are introduced into a 10L container at 500 deg C. At equil, 70% of the hydrogen iodide remains. a) Evaluate the equilibrium concentrations for each gas in mole L^-1. The initial concentration of HI is 0.4mol/L (4 moles in 10...

inverse tan. I just used to typing arctan stupid maple...

y=arctan(x) tany=x @x=0, tany=0 :. y = 0 @x=1, tany=1 :. y= pi/4 Now we find ∫ [tan (y)] . dy between 0 and pi/4. Answer is ln[sqrt(2)] The area under the inverse tan curve is equal to the total area of the rectangle (1 x pi/4) minus the area under the tany (w.r.t.y). So we get pi/4...