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Don't fret about a diagram. I'm pretty sure mine is correct. What's the length of the hypotenuse??

Justchillin: http://community.boredofstudies.org/showthread.php?p=1969023#post1969023

I was hoping justchillin could help me with this one. He likes polynomials... :)

Could you explain that? are you using the fact that the Area of a RHS triangle is ab/2 ? If so where did you get 5h from ? lmao, you sound like someone who plays too much Counter-Strike :D

I think you will do just fine. Especially when it comes to integration.

I don't know if I know how to do this... I'm just going to have a stab in the dark, seing as no-one else has replied. Random answer: S_n = 0 + 0 + 6 + 18 + 36 + 60 + 90 + ... + 3(n-2)(n-3) GP; S<sub>n</sup> = 6[(1-6^n-1)]/-5

Simply by the expansion of (a+b)ⁿ and some manipulation. This is VERY unlikely to be examined though. It's almost as likely as them asking us to derive Newtons Method of Root Approximation.

Last time I drank nothing was when I drank 'Nuka Cola'.

Did I say 'your best chance'? I mean't 'what I'd like to see you do'... Hehe, but, yes, true - sounds like that.

So I was correct! ;) PS. Nicely explained.

That's what I said! Pfft... just coz Slidey has a yellow name these days... :P

Your best chance is to injure yourself and fill in one of those forms.

The Bored Community has put me in charge of raising the 'HSC'ers Morale' ;) Just ask Slide_Rule or KFunk :D PS. On page 109 of the proof Andrew Wiles forgot something: (Q.E.D.)

Because if we have them arranged in a line there is a fixed FIRST and LAST position. If they are then joined into a circle we don't know who was last/first. So; (#ways the 2ppl can arrange themselves)(#ways the others can arrange themselves)(#ways the two groups can arrange themselves)...

I would of thought the answer would be either: 1. 0 2. Infinite 3. Something in between the last two. Correct me if I'm wrong ?

Haha, yes. But you get my point? PS. Next time give me a chance to edit ;)

The permutation of zero is 0? Since there are no things to permute... Depends on the type of 0. perm. of zero thing = 0 perm. of zero things = 0! = 0+1 = 2-1 = 2/2 = (0/0)! = e⁰ EDIT: Ignore (0/0)! :D

0! = 1 by definition. Don't get a headache trying to imagine it ;)

Thanks for the proof Rama. It's so simple once you read it. Why didn't I think of that? Oh well... if they ask us that tomorrow now we know how to do it.

Yes - ask the bank. (I hate these questions, sorry!)