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If my textbook has Anode Zn(s) + 2OH- (aq) --> ZnO s) + H2O(l) + 2e- Cathode MnO2(s) + 2H2O (l) + 2e- --> Mn(OH) 3(s) + OH-(aq) For the reactions, what would be the overall reaction? For overall reactions do i simply just add the 2 equations togethor without...

Anode reaction • Zn(s) + 2OH-(aq) >>>> Zn(OH)(2)(s)+ 2e- Cathode reaction • Ag2O(s) + H2O(l) + 2e- >>> 2Ag(s) + 2OH-(aq) Is this the overall reaction? Or should the Zn(OH) in the anode reaction match the product in the overall reaction? ( like the product up there is Zn hydroxide...

I sure wanna use them wisely haha. But i just get distracted so easily, no ipods, no leaving the library, friends everywheree ergh. i swear i work at like 30% of what i can do at home, and i have like 5" studys" a week and i cud do alotta work if i used it good...ly.

@ speedofsound, lolol thats exactly what i dont wanna do! cept i used to play COD.... hahas... yeah, i find it pretty hard to do work when everyone is around and distracting, and at home like i can do pure maths for like 4 hrs and its fine, but like during frees i just cant seem to work...

Ok, so our free periods last about 55 mins, and in year 11 we just played COD on the computers haha, but i wanna start making good use of my frees and i wanna know whats the best to do cause i've given up playing. Btw, our frees are in the library with computers. But like when i try to do...

Why is CH2BRCHOH called 2 bromoethanol? i thought it took the smallest number from where you count?