cambridge 4U
EX 3.3
Q5.
P(asec theta,btain theta) lies on the hyperbola [x^2/a^2] - [ y^2/b^2] =1. The tangent at P cuts the x axis at X and the y axis at Y. Show that PX/PY=sin^2 theta and deduce that if p is an extremity of a latus rectum, then PX/PY = [e^2-1]/[e^2]
plz help... tried...