Re: HSC 2013 4U Marathon
Alternatively, n^2-3n+2=(n-2)(n-1)
And notice that if it were to be prime, one bracket must be equal to 1, the other whatever it might be (as long as its positive)
(3-2)(3-1) = 1 \cdot 2 = 2 = \ \ $prime$
We could do the same for the other bracket where n=2, but...