Re: MX2 2015 Integration Marathon
I_n=I_{n-1}+\int_0^{2\pi}(1+\cos(\theta))^{n-1}\frac{d}{d\theta}(\sin(\theta))\, d\,\theta\\ = I_{n-1}+(n-1)\int_0^{2\pi}(1+\cos(\theta))^{n-2}\sin^2(\theta)\, d\theta \\ = I_{n-1}+(n-1)\int_0^{2\pi}(1+\cos(\theta))^{n-1}(2-(1+\cos(\theta)))\, d\theta \\ =...