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Im up to 30 for 3U, and Ive done about 10 for 2U so far... (the 2U ones are so boring!) Ill probably end up doing 50 for 3U and 20 for 2U

Re: Official BOS Mathematics Trial Examinations: Spring Edition. Will the questions be harder than this? Or relatively the same difficulty, or...MX2 Harder 3U difficulty?

Re: Official BOS Mathematics Trial Examinations: Spring Edition. MAYBE SPOILERS Part (i) y=-0.5gt^2+Vt\sin \theta \\ \dot{y}=-gt+V\sin \theta \\ t_{A}=\frac{V\sin \theta}{g} \ \ : [1] \ \ $Max height occurs at this time for projection A$ \\ \\ $Projection of B$ \\ x=Vt \ \ y=-0.5t^2+h \\ y=0...

Re: Official BOS Mathematics Trial Examinations: Spring Edition. MAYBE SPOLERS c) \ Let \ \ A(2am, am^2) \ \ B(2ab, ab^2) \ \ C(2ac, ac^2) \ \ D(2ad, ad^2) \\ \\ m_AB=\frac{b+m}{2a} \\ \therefore \tan \theta _{AB} = \frac{b+m}{2a} \\ \\ \therefore \cot \theta _{AB}=\frac{2a}{b+m} \\ \\ \cot...

Is this because there is only 1 way to pick nothing? Or is there a deeper reason?

Ok since I cant find that long post on asymptotes I made, Ill give a brief explanation: Take our function: f(x)=\frac{ax+k}{bx+m} The horizontal asymptote will be y=\frac{a}{b} And this can be derived from mere observation as well. Take any very large values of x, k and m are really...

I would want the school prefects to be like the Harry Potter prefects so I can have the same power as one of them and boss people around

This time I think Ive got it (deleted last post) \frac{n}{2} (n+(-1)^n) Works for 4 and 5 too. I now have to do proof of induction to verify it

Is it possible to find the number of white boxes (or black), in the nth triangle, if the triangles keep following the same pattern? The question originally asked to find the number of white boxes in the 5th triangle, but that was given to year 6. Im just wondering if its possible to generalise...

Best not to care about my method, I did the grunt work, Spiral was able to recognise a good way of doing this.

\frac{\sin{A+2A}}{\sin{A}}+\frac{\cos{A+2A}}{\cos {A}} \\ =\frac{\sin A \cos {2A}+\cos A \sin{2A}}{\sin {A}}+\frac{\cos A \cos 2A - \sin A \sin {2A}}{\cos {A}} \\ \\ = \frac{\sin A \cos 2A \cos A + \cos^2 A \sin 2A+ \sin A \cos A \cos 2A -\sin^2 A \sin 2A}{\sin A \cos A} \\ \\ =\frac{\sin 2A...

Re: Official BOS Mathematics Trial Examinations: Spring Edition. A solution to the question on page 5: \pi=\pi \int_{\frac{k}{2}} ^k e^{2x} \ dx \\ \\ 1=\frac{e^{2k}}{2}-\frac{e^k}{2} \\ 2=e^{2k}-e^{k} \\ \\ u=e^k \\ u^2-u-2=0 \\ \\ k=\ln 2

Is it err....realistic to aim for 100 Raw in 4U?

Is it realistic to aim for 90+ raw? (in 4u maths)

Have people gotten 100% in a 4U External before?

You can argue that only the victorious protagonists are the ones that matter to the plot of the story and the metaphor Orwell was trying to make about the communist movement. That he believes that the communist movement was of all lies and that victory only mattered to them, and that similarly...

Count the fact that all the science papers are just repeats, and that 70% of math trials are just utter lazy crap. But if this guy wants to do many papers, then let him do it I guess. Its possible this is either fake, or this guy doesnt know how much he is going to do

If you are really hardcore about this, Im going to say MX2: 200 MX1: 150 Physics: 50 Chemistry: 50 English: 100 For MX2 and MX1, practise is vital therefore you will need to do more past papers for this, do them regularly. For Sciences, knowledge is more needed than practise really, the more...

So we enter each respective formula for everything, then we drag the bottom corner of each formula box, and drag it down the 11 rows. we then enter the co-effiecients and we get our answers: