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I am pretty sure those square brackets should not exist. Without them the question makes perfect sense and is of an appropriate level of difficulty for MC. As the OP has written the question, the question does not make sense. There is no reason why the domain of f has to include anything...

It was the "HSC Exam Mark". I probably got about 117/120 raw. It was an easy year so state ranking ties would've been broken by assessment marks and 3U marks.

+1 on all counts.

Topography hey? :P.

Re: 2012 HSC MX2 Marathon Let f(x)=x*arcsin(x). As the product of two odd functions f is even, so it suffices to prove the assertion for 0<=x<1. f is the product of two positive and increasing functions on the interval 0<=x<=1. Hence 0=f(0)<=f(x) < f(1)=pi/2 for all -1 < x < 1.

Re: MX2 Integration Marathon If by do, you mean look up the answer using whichever resource he got those integrals from in the first place then yes he can.

Re: MX2 Integration Marathon Perhaps, but then again I am not asking for an explicit recurrence formula :). You should be able to integrate many integrals of this form without recursive methods.

Re: MX2 Integration Marathon Here is a question of a different flavour, but easier than most in this thread so far: $Outline a general procedure for integrating $\sin^n(x)\cos^m(x)$, where m and n are non-negative integers. Hint: You may need to split your procedure into cases according to...

Re: MX2 Integration Marathon Use the auxillary angle method to write the denominator as Rcos(x+alpha). Sec should be a function you know how to integrate.

Don't have any of their merch but am a big fan.

An MCS fan? Respect!

Am hyped! It is less heavy than in recent years but I am still pretty keen. It may get better upon second announcements.

Re: MX2 Integration Marathon U MAD BRO keep your integrals at the level of the MX2 integration topic. If you are interested in how to do these yourself, do outside research / ask in extracurricular. This thread is an inappropriate place to post them. @Rolpsy nice question...

Nope, the game is mixed doubles, a male must be paired with a female on each team.

I assume the question means: how many ways can you organise a single mixed doubles match from that pool of 12 players such that no married couple are both playing. (If instead we are organising 3 concurrent matches with the same condition then the problem is harder.) Choose the two men in the...

I took dexamphetamines once and have never felt so "switched on" in my life, but would definitely recommend against making something like that a habit. Get good sleep and eat healthy, with a bit of caffeine now and then to give you a kick.

Does anyone have a good LaTeX template for creating papers that look exactly like the BoS ones?

Or only fractionally more harmful than alcohol!

So then there is no distinction between you and someone who worked as hard as you until the last three weeks of semester and harder than you in the last three weeks of semester? It is easy enough to get a degree these days, you shouldn't expect charity for the sake of boosting your GPA.

The final question would be walking you through proof #3 in http://empslocal.ex.ac.uk/people/staff/rjchapma/etc/zeta2.pdf I presume.