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  1. trailblazer

    lol

    lol
  2. trailblazer

    Tomorrow

    Wow, that is impressive.
  3. trailblazer

    luke

    luke
  4. trailblazer

    2009 UMAT - How did it go?

    You Sir, have made my day.
  5. trailblazer

    2009 UMAT - How did it go?

    yes there are, couldn't believe it myself
  6. trailblazer

    Permutations and Combinations 3U Cambridge.

    "Bob is about to hang his eight shirts in the wardrobe. He has four different styles of shirt, two identical ones of each particular style. How many different arrangements are possible if no two identical shirts are next to one another?"
  7. trailblazer

    Dota Discussion

    rofl
  8. trailblazer

    lozzles

    lozzles
  9. trailblazer

    MX2 difficulty...

    lozzzleessss
  10. trailblazer

    Quick integration question

    LOL, thought you were doing some awesome method, before i realised it was the quotient rule.
  11. trailblazer

    Thirteen and Watchmen

    It doesn't matter what texts you do, its whether you analyze/compare with core text well. I have a friend who has found a High band 6 essay (20/20) which had "Mean Girls" as a related text. Gossip Girl is great btw.
  12. trailblazer

    Factorisation over the Complex Field

    5. Show that the roots of (z-1)^4 + (z+1)^4 = 0 are -+icot(pi/8) and +-icot(3pi/8) 6. Show that the roots of(z-1)^6 + (z+1)^6 = 0 are +-icot(pi/12), +-icot(5pi/12), +-i Help would be appreciated. Thanks in advance. Get In before Tim!
  13. trailblazer

    Rubics Cube

    Too good. Should ask him how he does it, I'm curious to find out.
  14. trailblazer

    Terry Lee TEXTbooks !

    I bought his 4U book off a yr 12 (2008) guy for $15
  15. trailblazer

    easy parametric

    Woah, coincidentally im stuck on the same question.
  16. trailblazer

    CSSA 2004 question

    i) y=ax^2 and y= 12x + 3 so by equating y, you will get ax^2 = 12x + 3 then moving to one side, you will get a quadratic equation in terms of x and a thus you get, ax^2 - 12x- 3 = 0 ii) Now they tell you that the line is a tangent, therefore it touches the parabola at one point. This means...
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