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Replace " 'Department(s)' " with " 'Division(s)' ".

Open circle at 0.

True - http://faculty.washington.edu/rag/CLASSES/m308/HANDOUTS/example.html.

I am of the opinion that "the more solutions, the better" with regards to solving problems in mathematics in different ways. It really helps you get used to various different methods, and in doing so you learn new techniques, so don't worry whether or not someone has already posted, your input...

There is no solution in the given interval. You could sketch both functions tan(x) and x on the same axes and see why. A more algebraic approach could include: Clearly x=0 is a solution, since tan(0)=0. Now, let f(x)=tanx-x ---> f'(x)=[sec(x)]^2-1 Now, for 0<x<pi /2, we...

Not sure if there's an easier way, but you could: 1). Open the provided link http://www.codecogs.com/latex/eqneditor.php (perhaps bookmark this) 2). Use this equation editor 3). When finished, copy the text into the reply box, with "[_tex]" before and "[_/tex]" [with no underscore ("_")]...

Someone of that stature would be a Professor by now, and there are no other ones listed here: http://www.asb.unsw.edu.au/schools/actuarialstudies/facultyandstaff/Pages/academicstaff.aspx

No - Macquarie's program was established 30 years before UNSW's. The lecturer who developed the program at UNSW was a graduate and former lecturer of Macquarie (not that it matters). Source: http://www.asb.unsw.edu.au/schools/Pages/MichaelSherris.aspx.

1).Use the substituion x=a(sec(u)) 2). To integrate sec(u) with respect to u note that d/du{sec(u)+tan(u)}=sec(u)[sec(u)+tan(u)], hence multiplying sec(u) by {sec(u)+tan(u)}/{sec(u)+tan(u)} will make things nice. 3). To transform the result from the variable u to x, draw up a right angled...

True. Reason is that people have been graduating from Macquarie with Actuarial Studies degrees for over 40 years, while UNSW has only offered the course for ~10 years (not sure on exact number). In terms of number of graduates from each University nowadays, i'd say they are quite similar.

Not entirely true. Law is no longer offered as a double degree, but the most popular double degrees with Actuarial Studies at Macquarie seem to be Applied Finance or Economics. It is also offered as a double degree with mathematics or statistics.

No. Just touch up on probability and loan repayments and you should be fine.

Trebla provides a nice algebraic proof of a well known result from Pascal's triangle. A non-algebraic (combinatorics) proof would go something similar to the following. Assume n and k are positive integers, with n>k. Consider Tom, who has (n-1) (distinct, distinguishable) blue marbles and 1...

True. Thanks for that Drongoski. Lesson learned: don't be lazy and copy the LaTeX code from other people, and if you do make sure you have the right line.

\textup{Second last line is incorrect. It should be } z^{-1}\left[=\frac{r\(\cos\theta\textcolor{red}{-}\sin\theta\)}{r^{2}}\right]= \frac{\overline{z}}{r^{2}}. Edited, thanks to Drongoski for picking up the typo.

No, not really; that'd be more useful for Engineering and Physics. Check out http://en.wikipedia.org/wiki/Actuarial_science. Although mathematical/statistical, it is fundamentally concerned with the applications that these disciplines have on commerce-related disciplines, such as finance and...

Agreed. Also, you'll be dealing more with statistics, rather than mathematics.

Just curious as to what the OP would consider "better". I mean some people use the word to reflect different factors, which may include: *quality of lecturers *variety of courses on offer *flexibility of timetabling *transport options (number of parking spaces, how close it is to public...

To the OP: Please define "good" and "bad" so we can validate/refute your post. I also see from your signature you would like to study engineering. Note that Macquarie University (to the best of my knowledge, don't quote me on this; check the handbook at www.handbook.mq.edu.au) does not offer...

Above is correct, but just remember: For x>0, exp{ln(x)}=x. For x<=0, exp{ln(x)} is not defined. [Whereas ln(exp{x})=x for all real x.] *Here exp{.}=e^.