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thanks guys

hmm, i'm still stuck >.< i got up to -3x +2 sin[2x] = 4S(1-2 cos[2x] + cos^2[2x])

thanks ill try it out now. answer was [-sin4x/4]

Hey guys... how do i start this, \int%20(8\cos^4{x}%20-8\cos^2{x}%20+1)%20dx thanks

dymocks at parramatta has them

Ohh ok thanks :D:D:D:D:D

ok thanks! i got 1, any ideas for 2. ?

Hi can someone explain how to sketch 1. | z - 3i | > | z + 2 | 2. w is a complex number and z is restricted as indicated. w = (z-2i)/(1-z) , |z| = 2 Thanks

get that ATAR you want, no point doing the subjects that will benefit you if you can't get into the course.

TAEYeoN!

just finished year 11 =) starting yr 12 next term >_< first time im getting morning and afternoon classes >_< i might just have to check out Iljimae! :D heres some info about coffee prince: The 1st Shop of Coffee Prince - DramaWiki you could use a break in studying for hsc :P

yeah not many good dramas out this year oh well need to start studying soon anyway so no distractions XD have you seen coffee prince? i thought that was pretty good.

kim myung min's acting is so freakin good! he played his character extremely well. jang guen suk wasn't too shabby himself

yeah its ok i guess, shes not that bad of an actor :)

touche! might just have to rewatch that drama :) its still the holidays :D

Lee Ji Ah? from beethoven virus yeah?

hey is that du ru mi in ur avatar? :D

(2/sqrt(2) +1)/2 = [2/sqrt(2) + 1] * 1/2 = 1/sqrt(2)+1

rodrigo y gabriela

the parabola can be written in the form (x-h)^2 = 4a(y-k) where (h,k) is the vertex. So for x^2 = 8(y-1), the vertex is (0,1) and the focus is (0,3).