A few questions about this option module
1) Is this option any good? My teacher wants to do this option because he specialises in it (although he's not a very good teacher anyway so i don't see the point in picking such an obscure option module).
2) How hard is this topic relative to the...
A few questions about this option module
1) Is this option any good? My teacher wants to do this option because he specialises in it (although he's not a very good teacher anyway so i don't see the point in picking such an obscure option module).
2) How hard is this topic relative to the other...
Hey guys. I'm not sure if this is the right place to post this, but anyway.
In 2009 i was accelerated and did 2unit and extension 1 maths for the HSC.
For extension 1 maths, my mark was 47/50. However this year I'm also doing extension two maths, so my mark for extension one maths will become...
When looking at past HSC solutions the answer always derives how to transform asinx + bcosx into Rsin(x + $)
I was wondering if we have to derive it as well, or can we simply use the formula for finding R and $ using:
R = sqrt(a^2 + b^2) and tan $ = b/a
???
A particle, whose displacement is x, moves in simple harmonic motion.
Find x as a function of t if:
acceleration = −4x
and if x = 3 and v = −6root3 when t = 0.
So when you've completed all of the available actual past HSC exams, what other papers do you do? What school's past papers are good to practice on and where can i access them?
oooh i see now. I was reading the exam report and marking a past exam late at night so i must've missed the minus sign. Thank you very much for pointing that out :uhhuh:
3.c) A particle moves in a straight line and its position at time t is given by:
x=1+sin4t+ (root3)cos4t
(i) Prove that the particle is undergoing simple harmonic motion about
x = 1.
When i was reading the exam report, they said it was incorrect to do the following:
a = −16 sin 4t −...
This was only in question 3, but i had no idea how to do it. :(
When the polynomial P(x) is divided by x^2-1 the remainder is 3x -1. What is the remainder when P(x) is divided by (x-1)
(answer = 2)
Bah I can't get it. For some reason i keep getting 1/5 instead of 2/5. Sorry to bother you again, but could you post a worked solution to the question?