Re: HSC 2015 4U Marathon - Advanced Level
lol apparently that perms and combs q is an imo question according to integrand......doubt it was posted as a legit question. maybe glitter can do it though
Re: HSC 2015 4U Marathon - Advanced Level
I have compiled ball's relevant posts. No where has he included in his proof that "g(x)+g(x)=g(x) so g(x) = 0."
Re: HSC 2015 4U Marathon - Advanced Level
Lol don't worry about Drsoccerball, he doesn't know what he's talking about/ can't admit that he couldn't solve the question.
But your solution is excellent!
Re: HSC 2015 4U Marathon - Advanced Level
so ur saying, that if ur given x +x^2 plus some term =y +y^2 then the only integer solutions are when x=0? just making sure before I post a counterexample
Re: HSC 2015 4U Marathon - Advanced Level
so ur argument is, for any diaphantine equation with an unequal number of terms, equality is achieved iff all the terms are zero? Or do u mean something else?
Re: HSC 2015 4U Marathon - Advanced Level
so ur argument is, if g (x)=x (non zero factor) +h (y) =0, then these zeroes occur only when x=0 and h (y) =0? This is clearly not true, and both of yours + soccerball's solutions wouldn't get more than 1 mark in the actual exam!
Re: HSC 2015 4U Marathon - Advanced Level
even a year 10 student can merely state the answer without any kind of proof. So ill assume u couldnt solve this one!
Re: HSC 2015 4U Marathon - Advanced Level
a polynomial is called self centered if it has integer coefficients and p (100) = 100. if p (x) is a self centred polynomial, what is the maximum number of integer solutions to p (k) =k^3?
Re: HSC 2015 4U Marathon - Advanced Level
suppose that a polynomial with integer coefficients satisfies P(100)=100. Find the maximum of integer solutions to P(k)=k^3 such a polynomial can have.