A particle is projected with speed V and angle of elevation alpha from point O on the edge of a cliff of height h. When the particle hits the ground its path makes an angle arctan(2tan(alpha)) with the horizontal.
Why is tan(beta)=vertical velocity/horizontal velocity?
Thanks.
I already calculated the coordinates of Q from tan(theta/2)tan(phi/2) = 1-e/1+e, but i don't know how to calculate the coordinates of Q from tan(theta/2)tan(phi/2) = 1+e/1-e.
The results you obtain in year 11 doesn't matter, but the content you learn in year 11 carries over to year 12. i.e The maths you learn in prelim is crucial in understanding the content in year 12 and the same is for the science courses etc.
Sketch the graph y=(x+1)^4/x^4+1. Use this graph to find the set of values of the real number k for which the equation (x+1)^4=k(x^4+1) has two real distinct roots.
I sketched the graph, but I don't understand what I should do after.
Thanks for your assistance.
I did that previously and ended up with the mass of the sun, the mass in Kepler's law refers to the central mass. I'm just unsure of how to calculate the mass of Pluto.
To find the stationary points of a curve the gradient must be equal to zero so sub 0 into y', i.e. 4(x-2)^3 =0, then sub each of the x values into the original equation to find the y coordinates.